Questions

MCQ

Take a timed test

7 questions · auto-graded multiple-choice test.

MCQ 11 Mark
The angle between the minute and hour hands of a clock at 8 : 30 is:
  • A
    80°
  • 75°
  • C
    60°
  • D
    105°
Answer
Correct option: B.
75°
We know that the hour of a clock completes one rotation in 12 hours.
Angle traced by the hour hand in 12 hours = 360°
Now,
Angle traced by the hour hand in 8 hours 30 minutes, i.e.
We also know that the minute hand of a clock completes one rotation in 60 minutes.
Angle traced by the minute hade in 30 minutes $=\Big(\frac{360}{60}\times30^{\circ}\Big)=180^{\circ}$
Required angle between the two hands of the clock = 255° - 180° = 75°
View full question & answer
MCQ 21 Mark
If the angles of a triangle are in $A.P.$ then the measures of one of the angles in radians is:
  • A
    $\frac{\pi}{6}$
  • $\frac{\pi}{3}$
  • C
    $\frac{\pi}{2}$
  • D
    $\frac{2\pi}{3}$
Answer
Correct option: B.
$\frac{\pi}{3}$
$\frac{\pi}{3}$
View full question & answer
MCQ 31 Mark
The radius of the circle whose arc of length $15\pi$ makes an angle of $\frac{3\pi}{4}$ radian at the centre is:
  • A
    $10\text{cm}$
  • $20\text{cm}$
  • C
    $11\frac{1}{4}\ \text{cm}$
  • D
    $22\frac{1}{2}\ \text{cm}$
Answer
Correct option: B.
$20\text{cm}$
  1. $20\text{cm}$
Solution:
$\theta=\frac{\text{Arc}}{\text{Radius}}$
$\Rightarrow\frac{3\pi}{4}=\frac{15\pi}{\text{Radius}}$
$\Rightarrow\frac{60}{3}$
$\Rightarrow20\text{cm}$
View full question & answer
MCQ 41 Mark
If the arac of the same langth in two circles subtend angles 65° and 110° at the center, the ratio of the circle is:
  • 22 : 13
  • B
    11 : 13
  • C
    22 : 15
  • D
    21 : 13
Answer
Correct option: A.
22 : 13
Let the angle subtended at the by the arec and radii of the first second circle $\theta_{1}$ and $\text{r}_{1}$ and $\theta_{2}$ and $\text{r}_{2}.$
We have,
$\theta_{1}=65^{\circ}=\Big(65\times\frac{\pi}{180}\Big)\ \text{radian}$
$\theta_{2}=65^{\circ}=\Big(110\times\frac{\pi}{180}\Big)\ \text{radian}$
$\theta_{1}=\frac{1}{\text{r}_{1}}$
$\Rightarrow \text{r}_{1}=\frac{1}{\big(65\times\frac{\pi}{180}\big)}$
$\Rightarrow \text{r}_{2}=\frac{1}{\big(110\times\frac{\pi}{180}\big)}$
$\frac{\text{r}_{1}}{\text{r}_{2}}=\frac{\frac{l}{\big(65\times\frac{\pi}{180}\big)}}{\frac{i}{\big(110\times\frac{\pi}{180}\big)}} $
$=\frac{110}{65}=\frac{22}{13}$
$\text{r}_{1}:\text{r}_{2}=22:13$
View full question & answer
MCQ 51 Mark
If OP makes 4 revolutions in on second the angular velocity in radians per seconds is:
  • A
    $\pi$
  • B
    $2\pi$
  • C
    $4\pi$
  • $8\pi$
Answer
Correct option: D.
$8\pi$
$\text{Angular velocity}=\frac{\text{Distance}}{\text{Time}}$
$=\frac{4\times2\pi}{1}$
$=8\pi\ \text{radians}$
View full question & answer
MCQ 61 Mark
If D, G and R denote respectively the number of degrees, grades and radians in an angle, then:
  • A
    $\frac{\text{D}}{100}=\frac{\text{G}}{90}=\frac{2\text{R}}{\pi}$
  • B
    $\frac{\text{D}}{90}=\frac{\text{G}}{100}=\frac{\text{R}}{\pi}$
  • $\frac{\text{D}}{100}=\frac{\text{G}}{100}=\frac{2\text{R}}{\pi}$
  • D
    $\frac{\text{D}}{90}=\frac{\text{G}}{100}=\frac{\text{R}}{\pi}$
Answer
Correct option: C.
$\frac{\text{D}}{100}=\frac{\text{G}}{100}=\frac{2\text{R}}{\pi}$
It is the relation between degree, grade and radian.
View full question & answer
MCQ 71 Mark
At 3 : 40, the hour and minute hands of a clock are inclined at:
  • A
    $\frac{2\pi^{\text{c}}}{3}$
  • B
    $\frac{7\pi^{\text{c}}}{12}$
  • $\frac{13\pi^{\text{c}}}{18}$
  • D
    $\frac{13\pi^{\text{c}}}{4}$
Answer
Correct option: C.
$\frac{13\pi^{\text{c}}}{18}$
We know that the hour of a clock completes one rotation in 12 hours = 360°
Angle traced by the hour hand in 12 hours = 360°
Now,
Angle traced by the hour hand in 8 hours 30 minutes, i.e.
We also know that the minute hand of a clock completes one rotation in 60 minutes.
Angle traced by the minute hade in 30 minutes $=\Big(\frac{360}{60}\times40^{\circ}\Big)=240^{\circ}$
Required angle between the two hands of the clock = 240° - 110° = 130°
Value of the angle (in radians) between the two hands of the clock $\Big(130\times\frac{\pi}{180}\Big)^{\text{c}}=\frac{13\pi^{\text{c}}}{18}$
View full question & answer