Question 14 Marks
The demand function of a watch is $p=6000-2 x$. Find the demand which maximizes the revenue and also find the corresponding price. OR Find the values of $x$ which maximize or minimize $f(x)=2 x^3+3 x^2-36 x+10$. Also find the maximum and minimum values of $f(x)$.
Answer
View full question & answer→$P=3000 \text { OR } 42 . x=2 ; f(x)=-34$