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Question 11 Mark
Define marginal cost.
Answer
The change in cost due to small change in production is called marginal cost.
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Question 21 Mark
What is marginal revenue?
Answer
The change in revenue due to small change in demand is called marginal revenue.
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Question 31 Mark
What are the stationery points of a function?
Answer
The points where maximum of minimum values occur are known as stationary points. The necessary condition to obtain a stationary value is $f'(x) = \frac{dy}{dx} = 0.$
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Question 41 Mark
How will be the second order derivative of a function at $x=a$ if function is maximum at $x = a?$
Answer
If the function is maximum at $x = a$ the second order derivative of a function at $x = a$ will be $f"(a) < 0.$ It means negative.
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Question 51 Mark
How will be the first order derivation of a function at $x= a$ if function is decreasing at $x=a?$
Answer
If the function is decreasing at $x = a$ the first order derivative of a function at $x = a$ will be $f'(a) < 0.$ It means negative.
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Question 61 Mark
State the rule for derivative product of two function of $x.$
Answer
If $u$ and $v$ are differentiable function of $x$ and if $y = u.v$ then $\frac{dy}{dx} = u(\frac{dv}{dx}) + v(\frac{du}{dx}).$
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Question 71 Mark
Find $\frac{d y}{d x}$ if $y=a^n$, $a$ is constant.
Answer
If $y=a^n$; $a =$ constant, then $\frac{d y}{d x} = 0.$
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Question 81 Mark
Find $f’(x)$ for the function $f’(x) = 50.$
Answer
Constant number is always $'0'.$
So, if function $f(x) = 50,$ then $f'(x) = 0.$
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Question 91 Mark
Find $\frac{d y}{d x}$ if $y=6 x^3+\frac{7}{2}+x^2+\frac{6}{5} x-8$.
Answer
Here, $y = 6x^3 + \frac{7}{2} + x^2 + \frac{6}{5}x - 8$
$\frac{dy}{dx}$ $=\frac{\mathrm{d}}{\mathrm{dx}}\left(6 x^3\right)+\frac{\mathrm{d}}{\mathrm{dx}}\left(\frac{7}{2} \mathrm{x}^2\right)+\frac{\mathrm{d}}{\mathrm{dx}}\left(\frac{6}{5} \mathrm{x}\right)-\frac{\mathrm{d}}{\mathrm{dx}}(8)$
  $=6 \frac{\mathrm{dy}}{\mathrm{dx}}\left(x^3\right)+\frac{7}{2} \frac{\mathrm{d}}{\mathrm{dx}}\left(x^2\right)+\frac{6}{5} \frac{\mathrm{d}}{\mathrm{dx}}(x)-\frac{\mathrm{d}}{\mathrm{dx}}(8)$
  $=6\left(3 x^2\right)+\frac{7}{2}(2 x)+\frac{6}{5}(1)-0$
  $=18 x^2+7 x+\frac{6}{5}$
$\therefore \frac{\mathrm{dy}}{\mathrm{dx}}=18 x^2+7 x+\frac{6}{5}$
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Question 111 Mark
State the formula of elasticity of demand.
Answer
Elasticity of Demand = $\frac { Percentage\ Change\ in\ demand }{ Percentage\ Change\ in\ Price }$
If we denote the demand as $x$ and Price is $p$ and the demand function $x = f(p)$ is given then,
Elasticity of demand = -$\frac{p}{x} \frac{d x}{d p}$
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Question 121 Mark
Define differentiation.
Answer
Let $f : A \rightarrow R$ and $a ∈ A,$ where $A$ is and open interval of $R.$
If $\lim _{h \rightarrow 0} \frac{f(a+h)-f(a)}{h}$ exists, then this limit of a function $f$ is called derivative at $x = a.$
It is denoted by $f'(a).$
The process of obtaining derivative of function is called differentiation.
Thus, $f'(a) = \frac{f(a+h)-f(a)}{h}$
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Question 131 Mark
What are the conditions for revenue function $R$ to be maximum?
Answer
The necessary and sufficient conditions for maximizing the revenue function $R$ are as follows:
$(i) \frac{dr}{dx} = 0$ and
$(ii) \frac{\mathrm{d}^2 \mathrm{R}}{\mathrm{dx}^2} = 0$
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Question 141 Mark
What is increment ratio of function $y=f(x) ?$
Answer
The increment ratio of a function $y=f(x)$ is $\frac{\delta y}{\delta x}$
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Question 161 Mark
If $x=$ demand and $p=$ price, then state the demand function.
Answer
If $x=$ demand and $p=$ price, then demand function is $x=f(p)$.
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Question 181 Mark
If the second order derivative of a function at $x=a$ Is positive, then what will be the function at $x=a ?$
Answer
If the second order derivative of a function at $x=a$ is positive, then the function will be minimum at $x=a$.
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Question 191 Mark
State the necessary condition for the stationary values of a function.
Answer
The necessary condition for the stationary values of a function $y=f(x)$ is $\frac{d y}{d x}$ or $f^{\prime}(x)$ $=0$.
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Question 201 Mark
If the increase in the price of toys Is $25 \%$, then its demand Is decreased by $20 \%$. Find the elasticity of demand of toys.
Answer
$0.8$
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Question 211 Mark
$f: A \rightarrow R .$ State the symbol of derivative for a member $x$ of $A$ in domain of $f ?$
Answer
$A \rightarrow R$, then the symbol of derivative for a member $x$ of $A$ in domain of $f$ is $f^{\prime}(x)$
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Question 221 Mark
If function $f: A \rightarrow R$, then what Is called the derivative of $f$ at a?
Answer
For the function $f: A \rightarrow R$, if $\lim _{h \rightarrow 0} \frac{f(a+h)-f(a)}{h}$ exists, then this limit is called the derivative of $f$ at a.
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Question 231 Mark
Profit function Is a function of which variable?
Answer
Profit function is a function of production $($demand$) x$.
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Question 241 Mark
Why is the negative sign taken in the formula of elasticity of demand?
Answer
The changes in the price and demand of an item are in opposite direction. Hence, the negative sign is taken in the formula of elasticity of demand.
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Question 251 Mark
By which derivative is marginal revenue or marginal cost obtained?
Answer
By using the first order derivative marginal revenue or marginal cost is obtained.
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Question 261 Mark
State the sufficient condition for maximum profit $P.$
Answer
The sufficient condition for maximum profit $P$ is $\frac{d^{2} P}{d x^{2}}<0( $Negative$).$
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Question 271 Mark
State the necessary condition for the stationary values of a function.
Answer
The necessary condition for the stationary values of a function $y=f(x)$ is $\frac{d y}{d x}$ or $f^{\prime}(x)$ $=0$.
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Question 281 Mark
$y=f(x)$. If function is maximum at $x=a$, then for a small positive number $h$, what is the value of $f(a) ?$
Answer
$y=f(x)$. If function is maximum at $x=a$, then for a small positive number $h, f(a)>f(a+h)$ and $f(a)$ $>f(a-h)$
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Question 291 Mark
State the sufficient condition for the function $f(x)$ to be minimum.
Answer
The sufficient condition for the function $f(x)$ to be minimum is $f^{\prime \prime}(x)>0$, l.e., $f^{\prime \prime}(x)$ is positive.
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Question 301 Mark
If a function is increasing at $x$ what will be its first derivative?
Answer
If a function is Increasing at $x$, then its first derivative will be positive, i.e., $f^{\prime}(x)>0 .$
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Question 321 Mark
$f(x)=4 x-1$, find $f^{\prime \prime}(x)$
Answer
$f(x)=4 x-1: f^{\prime}(x)=4$ and $f^{\prime \prime}(x)=0$
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Question 351 Mark
Write in words the rule of derivative of addition or subtraction of two functions of $x$.
Answer
The derivative of addition or subtraction of two functions of $x$ is equal to the addition or subtraction of derivatives of the functions.
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Question 371 Mark
$y =\frac{t^{2}}{5} .$ Find $\frac{d y}{d t}$ and $\frac{d y}{d x} ?$
Answer
$\frac{d y}{d t}=\frac{2 t}{5}$ and $\frac{d y}{d x}=0$
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Question 391 Mark
In which problems is differentiation used?
Answer
Differentiation is used in production, replacement pricing and other management decision problems.
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Question 401 Mark
When $\delta x \rightarrow 0$, what is the limit of $\frac{\delta y}{\delta x}$.
Answer
When $\delta x \rightarrow 0$, the limit of $\frac{\partial y}{\delta x}$ is $\frac{d y}{d x}$.
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Question 411 Mark
When $\delta x \rightarrow 0$, what is called the limit of $\frac{\delta y}{\delta x} \cdot ?$
Answer
When $\delta x \rightarrow 0$, then the limit of $\frac{\delta y}{\delta x}$ is called the derivative of $y$ with respect to $x$ and it is denoted by $\frac{\delta y}{\delta x}$.
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Question 421 Mark
What is increment ratio of function $y=f(x) ?$
Answer
The increment ratio of a function $y=f(x)$ is $\frac{\delta y}{\delta x}$
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Question 431 Mark
$y f(x)$. By which symbols is the increase in $x$ and $y$ denoted?
Answer
$y=f(x) .$ Then the increase in $x$ and $y$ is denoted by symbols $\delta x$ and $\delta y$ respectively.
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Question 441 Mark
How can we know how rapidly a function is changing at any point?
Answer
By using differentiation we can know how rapidly a function is changing at any point.
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Question 461 Mark
If $u$ and $v$ are differentiable functions of $x$ and $y = u v$, then rule for derivative for product of two functions of $x$ is as follows:
Answer
$\frac{d y}{d x}=u \cdot \frac{d v}{d x}+v \cdot \frac{d u}{d x}$
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Question 471 Mark
How will be the second order derivative of a function at $x=a$ if function is minimum at $x=a?$
Answer
If function is minimum at $x = a$ the second order derivative of a function at $x = a$ will be $f"(x) > 0.$
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Question 481 Mark
Find $\frac{\mathbf{d y}}{\mathbf{d x}}$ if $y=x^3+x^2+x-2$
Answer
Here, $y=x^3+x^2+x-2$
$\therefore \frac{d y}{d x} =\frac{d}{d x}\left( x ^3+ x ^2+ x -2\right)$
$=\frac{d}{d x}\left( x ^3\right)+\frac{d}{d x}\left( x ^2\right)+\frac{d}{d x}( x )-\frac{d}{d x}$
$=3 x^2+2 x+1-0$
$=3 x^2+2 x+1$
$(2)$
$\therefore \frac{d y}{d x}=3 x^2+2 x+11$
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Question 491 Mark
Why the negative sign is taken in the formulas of demand elasticity?
Answer
The ratio of elasticity of demand is negative as the change in price and demand of a commodity is in opposite direction. For convenience, the value of elasticity of demand is taken positive and hence the negative sign is taken in the formul$(A).$
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Question 501 Mark
How the marginal revenue can be obtained?
Answer
Marginal revenue can be obtained by taking the derivative of revenue function with respect to $x.$ Thus, when the demand is $x$ then marginal revenue $= \frac{dr}{dx}.$
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1 Marks Each - Statistics STD 12 Commerce Questions - Vidyadip