Question types

PART 2 : DIFFERENTIATION question types

80 questions across 6 question groups — pick any mix to generate a Statistics paper with step-by-step answer keys.

80
Questions
6
Question groups
5
Question types
Sample Questions

PART 2 : DIFFERENTIATION questions

One sample from each question group in this chapter. Select any group above to see the full set with answer keys.

Q 1MCQ1 Mark
What is the derivative of $y=x^5+\frac{1}{5}$ ?
  • $5 x^4$
  • B
    $x^5+\frac{1}{5}$
  • C
    $5 x^4+5$
  • D
    $x^5-\frac{1}{5}$

Answer: A.

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Q 2MCQ1 Mark
What is $\frac{d y}{d x}$ if $y=\frac{1}{\sqrt[3]{x}}$ ?
  • A
    $\frac{1}{3}$
  • B
    $\frac{1}{3 \sqrt{x}}$
  • $\frac{-1}{3 x^{\frac{4}{3}}}$
  • D
    $-3 x^2$

Answer: C.

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Q 3MCQ1 Mark
If the profit function $=P$, revenue function $=R$ and cost function $=C$ then what is the profit function?
  • A
    $R=P-C$
  • B
    $P=C-R$
  • C
    $C=R+P$
  • $P=R-C$

Answer: D.

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Q 4MCQ1 Mark
If the revenue function is $R=7 x ($where, $x=$ demand$),$ what is the unit price of the commodity?
  • $7$
  • B
    $0$
  • C
    $1$
  • D
    Can be any positive number

Answer: A.

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Q 5MCQ1 Mark
The total cost function of producing $x$ units is $C=5 x^2+100$. What is the marginal cost for $10$ units ?
  • A
    $600$
  • $100$
  • C
    $150$
  • D
    $200$

Answer: B.

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Q 224 Marks Each4 Marks
The demand function of a commodity is $p=\frac{675-
x^2}{10}$. Obtain the maximum revenue from it. Also
find the price of the commodity when revenue is maximum.
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Q 234 Marks Each4 Marks
The cost of producing $x$ tons of steel rods in a factory
is $C=5 x^2-100 x+100000$.
Find the production for minimum cost. Also find the
minimum cost
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Q 265 Mark Each5 Marks
The demand function of a commodity is $x=75-\frac
{3 p}{5}$ and the total cost of producing $x$ units is
$\frac{x^2}{5}+13 x+1000$. Obtain the maximum profit.
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Q 275 Mark Each5 Marks
The total cost of manufacturing $x$ mobile phones for a
mobile making company is $\frac{x^2}{20}+4 x+30$.
If the demand function of mobile phone is 
$(p=\frac{30-x}{2})$, where $p=$ price(in thousand rupees), how many mobile phones should be produced to earn maximum profit? What price should be fixed for the maximum profit ?
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Q 285 Mark Each5 Marks
During summer, a local potter makes one refrigerator in 5
thousand rupees using clay and other materials. The
demand function of such a refrigerator is $p=21-x$,
where $p=$ price (in thousand rupees) and $x=$
demand of refrigerator. How many refrigerators should
the potter make to get maximum profit? Also obtain
the maximum profit.
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