2 Marks Questions

Question 12 Marks

Compound (A) is formed when aniline is treated with $NaNO _2+ HCl$ at 273-278 K. Compound (B) is formed when cuprous chloride is added to (A).
Write the name of compound (A) and (B) and the equations of the chemical reactions involved.

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Question 22 Marks

Compound (A) is formed when benzene diazonium chloride is mixed with KI solution. Compound (B) is formed when ( A ) reacts with sodium in the presence of dry ether. Write the names of (A) and (B) and the equations of the chemical reactions involved.

Answer

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Question 32 Marks

Explain isocyanide test for primary amines.

Answer

When aliphatic and aromatic primary amine, is heated with chloroform and alcoholic (ethanolic) KOH, it forms foul smelling substance carbylamine or isocyanide. This is called isocyanide test.
Secondary and tertiary amines do not give this test.Therefore, this reaction is used in testing primary amines.

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Question 42 Marks

Draw the pyramidal shape of trimethyl amine.

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Question 52 Marks

Two isomeric compounds (A and B) have $C _4 H _{11} N$ molecular formula react with $HNO _2$ and forms compounds (C) and (D). C is hardly oxidised but it reacts immediately with Lucas reagent whereas $D$ reacts with Lucas reagent in 5 minutes and it also gives haloform reaction. Identify $A, B, C$ and $D$.

Answer

A and B are primary amines, which react HNO₂ and forms corresponding alcohols, C is a tertiary alcohol which is hardly oxidised and it reacts immediately with Lucas reagent and D is a secondary alcohols, hence it reacts with Lucas reagent in 5 minutes and due to

group it gives haloform reaction.

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Question 62 Marks

How will you make the following changes?
(i) Methyl alcohol to ethyl amine.
(ii) Ethanoic acid to ethanamine.

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Question 72 Marks

Ethyl amine is basic while acetamide is ampheteric. Explain the reason.

Answer

In ethylamine, the lone electron pair of Nitrogen of-NH₂ group is easily available to accept proton. Whereas in acetamide due to the presence of

group and its -I effect the lone electron pair of -NH₂ group is involved in resonance hence, it is not readily available to accept proton. There by, ethyl amine is basic whereas acetamide is amphoteric in nature.

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Question 82 Marks

Of all the methods of preparing amines identify by which aniline cannot be prepared?

Answer

Aniline cannot be prepared by the following methods:
(i) Reduction of nitriles
(ii) Reduction of amides
(iii) Reduction of oximes
(iv) Reductive amination of carbonyl compounds.

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Question 92 Marks

Write the reaction sequence required to prepare 2-Bromo-4-methyl aniline from p-amino toluene.

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Question 102 Marks

(i) Name the product obtained when excess of ethanol is treated with ammonia in the presence of Alumina?
(ii) How is methyl amine prepared from the following compounds? Give the equation.
(a) $CH _3- MgCl$
(b) $CH _3 COCl$

Answer

(i) When excess of ethanol is treated with ammonia in the presence of alumina, a mixture of primary, secondary and tertiary amines is obtained

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Question 112 Marks

Complete the following reactions:

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Question 122 Marks

How is p-nitroaniline is prepared by nitration of aniline? Explain with equations.

Answer

Due to the oxidising properties of conc. HNO₃ present in the nitration mixture, it oxidises aniline. Therefore, to control this reaction, the -NH₂ group is protected by acetylation of aniline before nitration.

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Chemistry 2 Marks Questions

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