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Chemistry 3 Marks Question

Coordination Compounds · Gujarat Board (GSEB) STD 12 Science (GSEB - English Medium). 2 questions.

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Question 13 Marks
Define isomerism and tell its types.
Answer
Isomerism : Two or more such compounds which have the same chemical formula (molecules) but have different arrangement of atoms are called isomers of each other and this property is called isomerism. Due to different arrangements of atoms, there is variation in one or more of their physical or chemical properties. There are two main types of isomerism in coordination compounds, which can again be classified into several parts :
(a) Stereoisomerism :
(1) Geometric isomerism
(2) Polarization isomerism
(b) Structural isomerism :
(i) Bond isomerism
(ii) Subcovalent isomerization or coordination isomerism
(iii) Ionization isomerism
(iv) Solvation isomerism or hydrate isomerism
(v) Ligand isomerism
(vi) Polymerization isomerism
(vii) Coordination position isomerism.
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Question 23 Marks
$Pt ( IV ), NH _3, Cl ^{-}$and $Na ^{+}$combine with each other to form seven types of complex compounds.
The following is :
$
\left[Pt\left(NH_3\right)_6\right] Cl_4
$
(i) Write the formulas of other six complex compounds.
(ii) Write the IUPAC names of these complex compounds.
(iii) Which of these complex aqueous solutions will have the highest conductivity?
(iv) Which of these complexes is non-ionic?
(v) Oxidation number of Pt in these complexes and also tell the coordination number.
Answer
(i) (a) $\left[ Pt \left( NH _3\right)_5 Cl ^2\right] Cl _3$
(b) $\left[ Pt \left( NH _3\right)_4 Cl _2\right] Cl _2$
(c) $\left[ Pt \left( NH _3\right)_3 Cl _3\right] Cl$
(d) $\left[ Pt \left( NH _3\right)_2 Cl _4\right]$
(e) $Na \left[ Pt \left( NH _3\right) Cl _5\right]$
(f) $Na _2\left[ PtCl _6\right]$
(ii) (a) Pentaammine platinum (IV) chloride
(b) Tetraammine dichlorido platinum (IV) chloride
(c) Triammine trichlorido platinum (IV) chloride
(d) Diammine tetrachlorido platinum (IV)
(e) Sodium ammine pentachlorido platinate (IV)
(f) Sodium hexachlorido platinate (IV)
(iii) The conductivity of complex $\left[ Pt \left( NH _3\right)_6\right] Cl _4$ will be highest because it gives maximum (five ion) in solution.
(iv) $\left[ Pt \left( NH _3\right)_6\right] Cl _4$ is non-polar.
(v) In all these complexes the oxidation number of Pt is 4 and coordination number is 6 .
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