Question 12 Marks
For the function $y = x^2$, if $x = 10$ and $\triangle\text{x}=0.1$. Find $\triangle\text{y}.$
Answer
View full question & answer→$\text{y}=\text{x}^2$
$\triangle\text{x}=0.1$
$\text{x}=10$
$\frac{\text{dy}}{\text{dx}}=2\text{x}$
$\Rightarrow\Big(\frac{\text{dy}}{\text{dx}}\Big)_{\text{x}=10}=20$
$\Rightarrow\triangle\text{y}=\text{dy}=\frac{\text{dy}}{\text{dx}}\text{dx}=20\times0.1=2$
$\triangle\text{x}=0.1$
$\text{x}=10$
$\frac{\text{dy}}{\text{dx}}=2\text{x}$
$\Rightarrow\Big(\frac{\text{dy}}{\text{dx}}\Big)_{\text{x}=10}=20$
$\Rightarrow\triangle\text{y}=\text{dy}=\frac{\text{dy}}{\text{dx}}\text{dx}=20\times0.1=2$