If 4a + 2b + c = 0, then the equation 3ax2 + 2bx + c = 0 has atleast one real root lying in the interval:
- (0, 1)
- (1, 2)
- (0, 2)
- None of these.
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$\text{f}(\text{x})=\sin\text{x}-\sin2\text{x}-\text{x}\text{ on }[0,\pi]$
f(x) = (x - 1) (x - 2)2 on [1, 2]
f(x) = x(x - 1)2 on [0, 1]
f(x) = x(x - 4)2 on the interval [0, 4]
$\text{f}(\text{x})=\cos2\Big(\text{x}-\frac{\pi}{4}\Big)\text{ on }\Big[0,\frac{\pi}{2}\Big]$
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