Question 11 Mark

Calculate the capacitance of a parallel plate capacitor having area $A=1 m^2$ and $d=1 mm$

Answer

→$\begin{aligned} & \text { Here, } A =1 m^2 \\ & \text { and } d= mm \\ & \quad=1 \times 10^{-3} m\end{aligned}$
For a parallel plate capacitor,
→ $
\begin{aligned}
C & =\frac{\varepsilon_0 A}{d} \\
\therefore C & =\frac{8.85 \times 10^{-12} \times 1}{1 \times 10^{-3}} \\
\therefore \quad C & =8.85 \times 10^{-9} F=8.85 nF
\end{aligned}
$

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