If you made a map of magnetic field lines at Melbourne in Australia, would the lines seem to go into the ground or come out of the ground?
Hence, magnetic field lines, due to the earth's magnetism would seem to come out of the ground.
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Alternate Answer
Soft iron has lower retentivity/Lower coercivity/Lower permeability/Smaller area of (B-H curve).$B_H=B_E\text{ }\cos\delta$
$B=B_E\text{ }\cos\text{ }60^\circ\Rightarrow B_E=2B$
At equator $\delta=0^\circ$
$\therefore\text{ }B_H=2B\cos\text{ }0=2B$
Alternate Answer
Ferromagnetic.$\theta = 60^\circ$
Alternate Answer
$\frac{\pi}{3}\text{radians}$
Alternate Answer
$\tan^{-1}\sqrt{3}$
The given magneticmaterial is paramagnetic in nature.

A magnet always has two poles.

$\text{U}(\overrightarrow{\text{r}_2})-\text{U}(\overrightarrow{\text{r}_1})=-\int\limits^{\vec{\text{r}}_2}_{\vec{\text{r}_1}} \vec{\text{B}}.\text{d}\vec{\text{l}}.$
Apply this equation to a closed curve enclosing a long atraicht wire. The RHS of the above equation is then
$-{\mu}_\text{o} \text{ i}$ by Ampere's law. We see that $\text{U}(\vec{\text{r}_2})\neq\text{U}(\vec{\text{r}_1})$ even when $\vec{\text{r}_2}=\vec{\text{r}_1}.$Can we have a magnetic acalar potential in this case?Explanation:
Denial of (a):
Tangent galvanometer is an instrument used to measure electric current; it cannot be used to the measure magnetic moment of a bar magnet.
Justification of (b) and (c):
Deflection magnetometer is used to measure
$\frac{\text{M}}{\text{B}_\text{H}}$ of a permanent bar magnet.Similarly, oscillation magnetometer is used to measure M BH of a bar magnet. So, if earth's horizontal field, BH, is known, then the magnetic moment of a bar magnet, M, can be measured.
Justification of (d):
Using deflection and oscillation magnetometers, we can calculate MBHMBH and M BH, respectively. Therefore, if we multiply the result obtained from both the instruments, then BH cancels out as $\frac{\text{M}}{\text{B}_\text{H}}\times\text{MB}_\text{H}=\text{M}^2$. Thus, the value of BH is not required.
Therefore, we can use both deflection and oscillation magnetometers if the earth's horizontal field is not known.

