Area of a plane loop is A . Current I is flowing through it and it is located in a uniform magnetic field $\overrightarrow{ B }$. Obtain an expression for torque $\vec{\tau}$ acting on it. If this loop is free to rotate then what will be its orientation in stable position?
Answer
$\vec{\tau}=\vec{m} \times \vec{B}$ If the direction of magnetic dipole is in the direction of magnetic field $\overrightarrow{ B }$, then electric current loop will be in stable position.
A plane loop of rectangular shape is moved in such a uniform magnetic field which is perpendicular to the plane of the loop. What is the direction and magnitude of induced current in the loop?
Answer
If a plane loop is rotated in any uniform magnetic field which is perpendicular to the plane of the loop, then no current flows in the loop and hence there will be no direction
of the current.
Write the direction $\otimes$ and $\odot$ of magnetic field produced at point $P$ in the given figure
Answer
(A) The electric current or electric field going inside the plane of paper is represented by a cross $\otimes$. (B) Electric current passing outside the plane of paper is represented by a dot $\odot$.
If on converting galvanometer of resistance G into ammeter, 1% of main current passes through the galvanometer, then what is the resistance of the shunt?
One alpha rays beam is incident along positive direction of + X-axis. It experiences a force along + Y-axis due to magnetic field. What is the direction of magnetic field?
Answer
Since alpha are positively charged particles, so their direction will be direction of current. Hence by Fleming's left-hand rule, the direction of magnetic field will be along Z-axis.
The spring used in a moving coil galvanometer is of low torsion constant. Why?
Answer
Current sensitivity and voltage sensitivity of a galvanometer are inversely proportional to torsion constant of the spring. Its value is kept low to increase the sensitivity
Current I flow through two parallel straight wires in the same direction/The wires are at a distance 2r from each other. What is the intensity of magnetic field atw the midpoint between the two wires?
Answer
Total magnetic field B = 0 as magnetic fields produced by two wires are equal and mutually opposite.
Two parallel wires are located very close to each other. The upper wire is fixed and the lower is free. What should be direction of current of suitable magnitude in both wires to stop the free wire? Give reason also.
Answer
The current should flow in the same direction due to force of attraction.
An electron is not deflected while passing through a uniform magnetic field. What is the direction of magnetic field?
Answer
Direction of magnetic field is either in the direction of motion of electron or opposite to it. Hence, $\theta=0^{\circ}$ or $180^{\circ}$ and therefore, $F = eVB \sin \theta=0$. So it will not be deflected.
There are 1000 turns in 1 meter length of the core of a solenoid and a current of 2A is flowing through it. What is the magnitude of magnetizing field H?
Answer
Given : $N=1000$ , $L =1 m$ , $I =2 A$ Magnetic field $H =\frac{ NI }{ L }$ $H =\frac{1000 \times 2}{1}=2000 A / m$ $=2 \times 10^3 A / m$ Ans.
One ampere is that electric current which in air or vacuum when flows through two long straight parallel wires at a distance of one meter produces a force of $2 \times 10^{-7} N / m$ in the wires.
Show that no work is done by magnetic Lorentz force on a moving charged particle in magnetic field.
Answer
It is because the direction of Lorentz force $\overrightarrow{ F }$ on charged particle is perpendicular to its velocity $\vec{v}$.e. displacement. $\overrightarrow{ F }=q(\vec{v} \times \overrightarrow{ B })$, therefore, work done by the force is $W =\overrightarrow{ F } \cdot \overrightarrow{ d }= F d \cos 90^{\circ}=0$ hence no work is done.
Why does a magnetic force exerts on a conducting wire kept in a magnetic field on passing current through it?
Answer
Due to flow of current, the free electrons of conducting wire moves in a definite direction with drift velocity and due to this magnetic force is exerted.
$ \overrightarrow{F}=(\overrightarrow{L} \times \overrightarrow{B})
$
A ring is uniformly charged. The total charge on ring is q and its radius is r. If it rotates on its axis by n rounds per second then what is the magnitude of produced magnetic field at the center?