M.C.Q. [1 Marks Each]

MCQ 11 Mark

“Variable” means that it:

✓
Can take different values.
B
Has a fixed value.
C
Can take only 2 values.
D
Can take only three values.

Answer

Correct option: A.

Can take different values.

Since, the value of a variable is not fixed.
So, variable means that it can take different values.
Hence, $(a)$ is correct option.

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MCQ 21 Mark

$x - 4 = -2$ has a solution:

A
$6$
✓
$2$
C
$-6$
D
$-2$

Answer

Correct option: B.

$2$

Given equation is $x - 4 = -2$
$\Rightarrow x = -2 + 4$
$\Rightarrow x = 2$
Hence, $(b)$ is correct option.

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MCQ 31 Mark

In algebra, $a \times b$ means ab, but in arithmetic $3 \times 5$ is:

A
$35$
B
$53$
✓
$15$
D
$8$

Answer

Correct option: C.

$15$

Given, in algebra, $a \times b = ab,$ which means $a$ is multiplied by $b$.
Also, in arithmetic, $3 \times 5$ means $3$ is multiplied by $5$.
$3 \times 5 = 15$
Hence, $(c)$ is correct option.

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MCQ 41 Mark

The equation $4x = 16$ is satisfied by the following value of $x$:

✓
$4$
B
$2$
C
$12$
D
$-12$

Answer

Correct option: A.

$4$

Given equations $4x = 16$
$\Rightarrow\frac{4\text{x}}{4}=\frac{16}{4}$
$\Rightarrow\text{x}=4$
Verification
Put $x = 4$ in Eq. $(i)$ then we get
$4 \times 4 = 16 \Rightarrow 16 = 16$
Therefore, value of $x$ is $4$.
Hence, $(a)$ is correct option.

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MCQ 51 Mark

The area of a square having each side $x$ is:

✓
$x \times x$
B
$4x$
C
$x + x$
D
$4 + x$

Answer

Correct option: A.

$x \times x$

Here, side $= x$
We know that, area of square = Side $\times$ Side
Area of square $= x \times x$
Hence, $(a)$ correct option.

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MCQ 61 Mark

$\frac{4}{2}=2$ denotes a:

✓
Numerical equation.
B
Algebraic expression.
C
Equation with a variable.
D
False statement.

Answer

Correct option: A.

Numerical equation.

We know that, an equation which contains only numbers is called a numerical equation.
Since, equation $\frac{4}{2}=2$ contains only numbers, so it is a numerical equation.
Hence, $(a)$ is correct option.

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MCQ 71 Mark

Which of the following is an equation?

A
$x + 1$
B
$x - 1$
✓
$x - 1 = 0$
D
$x + 1 > 0$

Answer

Correct option: C.

$x - 1 = 0$

We know that, an expression with a variable, constants and the sign of equality $(=)$ is called an equation.
So, $x - 1 = 0$ is an equation.
Hence, $(c)$ is correct option.

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MCQ 81 Mark

If each match box contains $50$ matchsticks, the number of matchsticks required to fill n such boxes is:

A
$50 + n$
✓
$50n$
C
$50 ÷ n$
D
$50 - n$

Answer

Correct option: B.

$50n$

Given, each matchbox contains $50$ matchsticks.
Then, total number of matchsticks in n boxes = Matchsticks in one box $\times $ Total boxes
$= 50 \times n = 50n$
Hence, $(b)$ is correct option.

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MCQ 91 Mark

$\frac{\text{q}}{2}=3$ has a solution:

✓
$6$
B
$8$
C
$3$
D
$2$

Answer

Correct option: A.

$6$

Given equation is $\frac{\text{q}}{2}=3$
$\Rightarrow\frac{\text{q}}{2}\times2=3\times2$
$\Rightarrow\text{q}=6$
Hence, $(a)$ is correct option.

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MCQ 101 Mark

Which of the following represents $6 \times x$

✓
$6x$
B
$\frac{\text{x}}{6}$
C
$6 + x$
D
$6 - x$

Answer

Correct option: A.

$6x$

Given that, $6 \times b = 6b$
Hence, $(a)$ is correct option.
Note: In algebra multiplication, sign does not show in the product (result).

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MCQ 111 Mark

If the perimeter of a regular hexagon is $x$ metres, then the length of each of its sides is:

A
$(x + 6)$ metres.
✓
$(x ÷ 6)$ metres.
C
$(x - 6)$ metres.
D
$(6 ÷ x)$ metres.

Answer

Correct option: B.

$(x ÷ 6)$ metres.

Given, perimeter of regular hexagon is $x$ metres, Number of sides in regular hexagan $= 6$
Length of each sides
$=\frac{\text{Perimeter of regular hexagon}}{\text{Number of sides in hexagon}}$
$=\frac{\text{x}}{6}\text{metres}$
Hence, $(b)$ is correct option.

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MCQ 121 Mark

Amulya is $x$ years of age now. $5$ years ago her age was:

A
$(5 - x)$ years.
B
$(5 + x)$ years.
✓
$(x - 5)$ years.
D
$(5 ÷ x)$ years.

Answer

Correct option: C.

$(x - 5)$ years.

iven, Amulya’s present age $= x$
$5$ years ago, Amulya’s age $= (x - 5)$ years
Hence, $(c)$ is correct option.

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MCQ 131 Mark

I think of a number and on adding $13$ to it, I get $27$. The equation for this is:

✓
$x - 27 = 13$
B
$x - 13 = 27$
C
$x + 27 = 13$
D
$x + 13 = 27$

Answer

Correct option: A.

$x - 27 = 13$

Let the number be $x$.
According to the question, $x + 13 = 27$
Hence, $(d)$ is correct option.

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MCQ 141 Mark

The perimeter of the triangle shown in Fig. is:

✓
$2x + y$
B
$x + 2y$
C
$x + y$
D
$2x - y$

Answer

Correct option: A.

$2x + y$

We know that, perimeter of the triangle = Sum of all sides of triangle
Here, sides are $x, x$ and $y.$
Perimeter of the triangle $= x + x + y = 2x + y$
Hence, $(a)$ is correct option.

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MCQ 151 Mark

Which of the following equations has $x = 2$ as a solution?

A
$x + 2 = 5$
✓
$x - 2 = 0$
C
$2x + 1 = 0$
D
$x + 3 = 6$

Answer

Correct option: B.

$x - 2 = 0$

To get solution as $x = 2$, solve each equation.
For option $(a)$,
$x + 2 = 5$
$\Rightarrow x = 5 - 2$
$[$transposing $+2$ to $RHS]$
$\Rightarrow x = 3$
For option $(b)$,
$x - 2 = 0$
$\Rightarrow x = 2$
$[$transposing $-2$ to $RHS]$
For option $(c),$
$2x + 1 = 0$
$2x = -1 [$transposing $+1$ to $RHS]$
$\Rightarrow\frac{2\text{x}}{2}=\frac{-1}{2}$
$[$dividing both sides by $2]$
$\Rightarrow\text{x}=\frac{-1}{2}$
For option $(d),$
$\Rightarrow x + 3 = 6$
$\Rightarrow x = 6 - 3 [$transposing $+3$ to $RHS]$
$\Rightarrow x = 3$
Therefore, we get $x = 2$ as a solution in option $(b)$ only.
Hence, $(b)$ is correct option.

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MCQ 161 Mark

In algebra, letters may stand for:

A
Known quantities.
✓
Unknown quantities.
C
Fixed numbers.
D
None of these.

Answer

Correct option: B.

Unknown quantities.

In algebra, letters may stand for unknown quantities.
Hence, $(b)$ is correct option.

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MCQ 171 Mark

Savitri has a sum of $Rs\ x$. She spent $Rs\ 1000$ on grocery, $Rs\ 500$ on clothes and $Rs\ 400$ on education, and received $Rs\ 200$ as a gift. How much money (in $Rs$) is left with her?

✓
$x - 1700$
B
$x - 1900$
C
$x + 200$
D
$x - 2100$

Answer

Correct option: A.

$x - 1700$

Given,
Savitri has total money $= Rs. x$
Spent on grocery $= Rs. 1000$
Spent on clothes $= Rs. 500$
Spent on education $= Rs. 400$
Received as a gift $= Rs. 200$
Then, money left with her $= Rs. {x - [1000 + 500 + 400 - 200]}$
$= Rs.{x - [1900 - 200]}$
$= Rs.{x - 1700}$
Hence, $(a)$ is correct option.

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MCQ 181 Mark

$10 - x$ means:

A
$10$ is subtracted $x$ times.
B
$x$ is subtracted $10$ times.
✓
$x$ is subtracted from $10$.
D
$10$ is subtracted from $x$.

Answer

Correct option: C.

$x$ is subtracted from $10$.

$10 - x$ means $x$ is subtracted from $10.$
Hence, $(c)$ is correct option.

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MCQ 191 Mark

If $x$ takes the value $2$, then the value of $x + 10$ is:

A
$20$
✓
$12$
C
$5$
D
$8$

Answer

Correct option: B.

$12$

Given, expression $= x + 10$
On substituting $x = 2,$ we get$ x + 10 = 2 + 10 = 12$
Hence, $(b)$ is correct option.

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MCQ 201 Mark

For any two integers $x$ and $y$, which of the following suggests that operation of addition is commutative?

✓
$x + y = y + x$
B
$x + y > x$
C
$x - y = y - x$
D
$x × y = y × x$

Answer

Correct option: A.

$x + y = y + x$

Let $a$ and $b$ be two integers, then in commutative property
$a + b = b + a$
Here, $x$ and $y$ are integers.
Then, $x + y = y + x$
Hence, $(a)$ is correct option.

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MCQ 211 Mark

The expression obtained when $x$ is multipled by $2$ and then subtracted from $3$ is:

A
$2x - 3$
B
$2x + 3$
✓
$3 - 2x$
D
$3x - 2$

Answer

Correct option: C.

$3 - 2x$

First $x$ is multiplied by $2.$
$2 × x - 2x$
Now, $2x$ is subtracted from $3 = 3 - 2x$
Hence, $(c)$ is correct option.

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MCQ 221 Mark

Kanta has $p$ pencils in her box. She puts $q$ more pencils in the box. The total number of pencils with her are:

✓
$p + q$
B
$pq$
C
$p - q$
D
$\frac{\text{p}}{\text{q}}$

Answer

Correct option: A.

$p + q$

Given, pencils in Kanta’s box $= p$
When $q$ more pencils are put in the box, then total number of pencils $= p + q$
Hence, $(a)$ is correct option.

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MCQ 231 Mark

Which of the following equations does not have a solution in integers?

A
$x + 1 = 1$
B
$x - 1 = 3$
✓
$2x + 1 = 6$
D
$1 - x = 5$

Answer

Correct option: C.

$2x + 1 = 6$

We know that, integers are $-4, -3, -2, -1, 0, 1, 2, 3, 4$
Now, we check the equations.
For option $(a).$
$x + 1 = 1$
$\Rightarrow x = 1 - 1$ [transposing $+1$ to $RHS$]
$\Rightarrow x = 0$, which is an integer.
For option $(b).$
$x - 1 = 3$
$\Rightarrow x = 3 + 1$ [transposing $-1$ to $RHS$]
$\Rightarrow x = 4,$ which is an integer.
For option $(c),$
$2x + 1 = 6$
$\Rightarrow 2x = 6 - 1$ [transposing $+1$ to $RHS$]
$\Rightarrow 2x = 5$
$\Rightarrow\frac{2\text{x}}{2}=\frac{5}{2}$ [dividing both sides by $2$]
$\Rightarrow\text{x}=\frac{5}{2},$ which is not an integer.
For option $(d).$
$1 - x = 5$
$\Rightarrow -x = 5 - 1$ [transposing $+1$ to $RHS$]
$\Rightarrow -x = 4$
$\Rightarrow x = -4$, which is an integer. [dividing both sides by $-1$]
Hence, $(c)$ is correct option.

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MATHS M.C.Q. [1 Marks Each]

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