MATHS BLANKS [1 Marks Each]

x + y + z is an expression which is neither monomial nor binomial.
Solution:
Since, x + y + z has three terms, so it is trinomial.
Hence, x + y + z is an expression which is neither monomial nor binomial.

Sum or difference of two like terms is a like term.
Solution:
Sum or difference of two like terms is a like term, e.g.
138x²y - 125x²y = 13x²y

On adding a monomial 2x or –4y² or –z to - 2x + 4y² + z, the resulting expression becomes a binomial.
Solution:
We can add 2x, -4y² and -z to the expression to make it binomial.
⇒ 2x + (-2x + 4y² + z) = 4y² + z
⇒ -4y² + (-2x + 4y² + z) = -2x + z
⇒ -z + (-2x + 4y² + z) = -2x + 4y²
Hence, on adding a monomial 2x or -4y² or - z to -2x + 4y² + z, the resulting expression becomes a binomial.

Number of terms in a monomial is one.
Solution:
Number of terms in a monomial is one.

Like terms in the expression n(n + 1) + 6(n - 1) are n and 6n.
Solution:
We have, n(n + 1)+ 6(n – 1) = n² + n + 6n - 6
Hence, like terms in the expression n(n + 1) + 6(n - 1) are n and 6n.

If (x²y + y² + 3) is subtracted from (3x²y + 2y² + 5), then coefficient of y in the result is 2x².
Solution:
We have, (3x²y + 2y² + 5) - (x²y + y² + 3)
= 3x²y + 2y² + 5 - x²y - y² - 3
= 2x²y + y² + 2
Coefficient of y = 2x²

If Rohit has 5xy toffees and Shantanu has 20yx toffees, then Shantanu has 15xy more toffees.
Solution:
We have, Rohit has toffees = 5xy
Shantanu has toffees = 20yx
Difference = 20xy - 5xy = 15xy
Hence, Shantanu had 15xy more toffees.

The unlike terms in perimeters of following figures are 2y and 2y².
Solution:
In Fig. (i),
Perimeter = Sum of all sides
= 2x + y + 2x + y = 4x + 2y
In Fig. (ii),
Perimeter = Sum of all sides
= x + y² + x + y² = 2x + 2y²
Unlike terms in perimeters are 2y and 2y².

-a - b - c is same as -a - (b + c).
Solution:
We have, -a - b - c = -a - (b + c)
So,-a - b - c is same as -a - (b + c).
[by taking common (-) minus sign]

-5a²b and - 5b²a are unlike terms.
Solution:
-5a²b and -5b²a are unlike terms as they do not have same algebraic factor.

3a²b and - 7ba² are like terms.
Solution:
3a²b and - 7ba² are like terms as both have same algebraic factor a²b.