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4 questions · self-marked practice — reveal the answer and mark yourself.

Question 11 Mark
$\Big(\frac{\text{a}}{\text{b}}\Big)^{-16}=\ ...... $
Answer
$\Big(\frac{\text{a}}{\text{b}}\Big)^{-16}=\Big(\frac{\text{b}}{\text{a}}\Big)^{16}$

Solution:

We know,

$\Big(\frac{\text{a}}{\text{b}}\Big)^{-1}=\Big(\frac{\text{b}}{\text{a}}\Big)^1$

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Question 21 Mark
$(-2)^{-5}= ......$
Answer
$(-2)^{-5}=\frac{-1}{32}$
Solution:
$\Big[\text{Since}\Big(\frac{\text{a}}{\text{b}}\Big)^{-1}=\Big(\frac{\text{b}}{\text{a}}\Big)^1\Big]$
$(-2)^{-5}=\Big(\frac{-2}{1}\Big)^{-5}=\Big(\frac{1}{-2}\Big)^5$
$=\frac{(1)^5}{(-2)^5}=\frac{1\times1\times1\times1\times1}{(-2)\times(-2)\times(-2)\times(-2)\times(-2)}$
$=\frac{1}{-32}$
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Question 31 Mark
If 9 × 3n = 36, then n = .......... .
Answer
If 9 × 3n = 36, then n = 4.

Solution:

If 9 × 3n = 36

⇒ 32 × 3n = 36

⇒ 3(2+n) = 36

Equating the powers:

⇒ (2 + n) = 6

⇒ n = (6 - 2) = 4

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Question 41 Mark
(8)0 = ?
Answer
(8)0 = 1

Solution:

By definition, we have a0 = 1 for every integer a.

$\therefore$ (8)0 = 1

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