3 Marks Question

Question 13 Marks

In the number line given below, what decimal numbers do the boxes labelled ‘u’, ‘v’, ‘w’, and ‘x’ represent?

Answer

There are 10 divisions between 6.1 and 6.6 , so each division is a tenth part of 0.5 or $\frac{5}{10}$, i.e., $\frac{5}{100}=0.05$ units. Therefore, the first division after 6.1 , denoted by V, represents the number 6.15 , while the fourth division, denoted by V, represents the number 6.3 , the seventh division, denoted by 'w', represents the number 6.45 , and the first division after 6.6 , denoted by ' x' represents the number 6.65 .

View full question & answer→

Question 23 Marks

Ravi delivers 2.5 kg, 3.2 kg, and 4.1 kg of vegetables to a store in the first three days. In 7 days, he delivers 20 kg of vegetables. What is the total quantity of vegetables delivered in the last four days?

Answer

The total vegetables delivered in the first 3 days:
2.5 kg + 3.2 kg + 4.1 kg = 9.8 kg
Total vegetables delivered in 7 days = 20 kg (Given)
Vegetables delivered in the last 4 days = 20 kg – 9.8 kg = 10.2 kg
Ravi delivered 10.2 kg of vegetables in the last four days. 5.

View full question & answer→

Question 33 Marks

Arrange the following numbers in descending order :
(a) 10.98, 10.089, 10.809, 10.908, 10.981
(b) 22.31, 22.13, 22.331, 22.313, 22.133

Answer

(a) We will write the given decimal numbers as:
10.980, 10.089, 10.809, 10.908, 10.981
Hence, the given decimals in descending order are:
10.981, 10.98, 10.908, 10.809, 10.089
(b) We will write the given decimal numbers as:
22.310, 22.130, 22.331, 22.313, 22.133
Hence, the given decimals in descending order are:
22.331, 22.313, 22.31, 22.133, 22.13

View full question & answer→

Question 43 Marks

(a) Find the value of $7 \frac{9}{100}-3 \frac{5}{100}$ ?
(b) What will be the sum of $6 \frac{4}{10} \frac{8}{100}$ and $14 \frac{5}{10} \frac{3}{100}$ ?

Answer

(a)
$\begin{array}{r}
7 \frac{9}{100} \\
-3 \frac{5}{100} \\
\hline 4 \frac{4}{100}\end{array}$
(b)
$\begin{aligned} & 6 \frac{4}{10} \frac{8}{100}+14 \frac{5}{10} \frac{3}{100} \\ = & (6+14)+\left(\frac{4}{10}+\frac{5}{10}\right)+\left(\frac{8}{100}+\frac{3}{100}\right) \\ = & 20+\frac{9}{10}+\frac{11}{100}=20+\frac{9}{10}+\frac{10}{100}+\frac{1}{100} \\ = & 20+\frac{9}{10}+\frac{1}{10}+\frac{1}{100} \\ = & 20+\frac{10}{10}+\frac{1}{100}=20+1+\frac{1}{100}=21 \frac{1}{100}\end{aligned}$

View full question & answer→

Question 53 Marks

The lengths of the body parts of an ant are as follows :
Head $=\left(1 \frac{4}{10}\right)$ units,
Thorax $=\left(2 \frac{6}{10}\right)$ units
Abdomen $=\left(3 \frac{7}{10}\right)$ units.

Find its total length of the ant.

Answer

Total length of ant $=1 \frac{4}{10}+2 \frac{6}{10}+3 \frac{7}{10}$
$=(1+2+3)+\left(\frac{4}{10}+\frac{6}{10}+\frac{7}{10}\right)=6+\frac{17}{10}$
$\begin{array}{l}=6+\frac{10}{10}+\frac{7}{10} \\ =6+1+\frac{7}{10} \\ =7+\frac{7}{10}\end{array}$
So, the total length is 7 units and 7 one-tenths, i.e., $7 \frac{7}{10}$ units

View full question & answer→

MATHS 3 Marks Question

Test yourself on this topic