MATHS 3 Marks Question

(a) (ab + be) + (bc + ca)
= ab + (bc + be) + ca
= ab + (1 + 1 )bc + ca
= ab + 2 be + ca

(b) 3x – y + z,2y – 5z and 3z – 4x (3x – y + z) + (2y – 5z) + (3z – 4x)
= (3x – 4x) + (-y + 2y) + (z – 5z + 3z)
= (3 – 4)x + (-1 + 2)y + (1 -5 + 3)z
= -x+y-z

(c) 3p – q + 5r, q – 2r and 3r – 2p + 7q
= (3p – q + 5r) + (q – 2r) + (3r – 2p + 7q)
= (3p – 2p) + (—q + q + 7g) + (5r – 2r + 3r)
= -p + 7q + 6r

Starting from 1 each shape of the given pattern is obtained by adding 1 vertex to the previous shape.
So, the number pattern involved is 1, 2, 3, 4, 5, 6, 7,…

And, next two shapes are :