2 Marks Questions

Question 12 Marks

Show the shape of the distance-time graph for the motion in the following cases
(a) A car moving with a constant speed.
(b) A car parked on a road side.

Answer

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Question 22 Marks

While going for a school picnic, Paheli decided to note the reading on the odometer of the bus after every 30 min till the end of the journey. Later on she recorded her readings in table.
Odometer reading at different times of the journey

Time (AM)	Odometer readings	Distance from the starting point
8:00	36540 km	0 km
8:30	36560 km	20 km
9:00	36580 km	40 km
9:30	36600 km	60 km
10:00	36620 km	80 km

(i) Can you tell how far was the picnic spot from the school?
(ii) Can you calculate the speed of the bus?
(iii) Looking at the table, Boojho asked Paheli whether she can tell how far they would have travelled till 9:45 AM.

Answer

(i) 80 km
(ii) Total distance $=80 km$
Total time $=2 h$
Speed $=\frac{\text { Total distance }}{\text { Total time }}=\frac{80}{2}=40 km / h$
(iii) As they are moving with constant velocity, so the distance travelled till 9:45 AM is 70 km.

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Question 32 Marks

(a) Name the watch that have an electric circuit with one or more cells.
(b) Name the ancient time measuring device.

Answer

(a) Electric watch:-
A watch that has an electric circuit powered by one or more cells.
(b) Sundial:-
An ancient device used to measure time using the position of the sun’s shadow.

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Question 42 Marks

Write the use of odometer in the vehicle.

Answer

An odometer is used to measure the total distance travelled by a vehicle.
It helps in:
Tracking the distance for maintenance schedules.
Calculating fuel efficiency.
Recording the mileage for journeys.

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Question 52 Marks

A car travelling at a speed of 60 km/h takes 20 min to reach its destination. What distance has the car covered?

Answer

We can calculate the distance using the formula:
Distance $=$ Speed × Time
Step 1: Convert time to hours
20 minutes $=\frac{20}{60}$ hours $=\frac{1}{3}$ hours
Step 2: Use the formula
Distance $=60 \times \frac{1}{3}=20 km$
The car has covered 20 km

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Question 62 Marks

Which of the following distance-time graphs shows a truck moving with speed which is not constant?

Answer

As, we know that if the distance-time graph is a straight line, the motion is said to be uniform and if the graph between distance-time graph is not straight line, then the motion is said to be non-uniform. So, option (c) is correct.

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Question 72 Marks

Suppose, the two photographs, shown in two figures had been taken at an interval of 10 s. If a distance of 100 m is shown by 1 cm in these photographs, then calculate the speed of the circled car.

Answer

Distance covered by the car is 0.5 cm which is measured by scale in this photograph.
Given, $1 cm=100 m$, then $0.5 cm=50 m$
So, distance travelled by the car $=50 m$
Time interval $=10 s$
$
\text { Speed }=\frac{\text { Distance }}{\text { Time }}=\frac{50}{10}=5 m / s
$

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Question 82 Marks

A car moves with a speed of 40 $km / h$ for 15 min and then with a speed of 60 $km / h$ for the next 15 min.
The total distance covered by the car is
(a) 100 km
(b) 25 km
(c) 15 km
(d) 10 km

Answer

Given, speed for first 15min = 40$km / h$
Speed for next 15min = 60$km / h$
As, we know that distance $=$ Speed $\times$ Time
So, for first 15 min, distance travelled
$=40 \times \frac{15}{60}=10 km \quad\left(1 min=\frac{1}{60} h\right)$
For second 15 min, distance travelled
$=60 \times \frac{15}{60}=15 km \quad\left(1 min=\frac{1}{60} h\right)$
So, total distance $=15+10=25 km$

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Question 92 Marks

The odometer of a car reads 57321 km when the clock shows the time 08:30 AM. What is the distance moved by the car, if at 08:50 AM, the odometer reading has changed to 57336 km? Calculate the speed of the car in km/min during this time. Express the speed in $km / h$ also.

Answer

As we know that,
Speed $=\frac{\text { Distance covered }}{\text { Time taken }}$
Given, distance covered
$
=57336-57321=15 km
$
Time taken $=8: 50 AM -8: 30 AM =20 min$
So, speed $=\frac{15}{20}=\frac{3}{4} km / min$
Now, speed in $km / h$ is given by $\frac{3}{4} \times 60$
$
=45 km / h \quad\left[1 \min =\frac{1}{60} h\right]
$

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Question 102 Marks

The distance between two stations is 240 km. A train takes 4 h to cover this distance. Calculate the speed of the train.

Answer

As we know that, the speed of a body is given by
$\begin{aligned} \text { Speed } & =\frac{\text { Distance travelled }}{\text { Time taken }} \\ & =\frac{240}{4}=60 km / h \end{aligned}$

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Question 112 Marks

Which of the following are not correct?
(a) The basic unit of time is second.
(b) Every object moves with a constant speed.
(c) Distances between two cities are measured in kilometres.
(d) The time period of a given pendulum is not constant.
(e) The speed of a train is expressed in $m / h$.

Answer

(b), (d) and (e) are not correct.

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Question 122 Marks

Classify the following as motion along a straight line, circular or oscillatory motion.
(a) Motion of your hands while running.
(b) Motion of a horse pulling a cart on a straight road.
(c) Motion of a child in a merry-go-round.
(d) Motion of a child on a see-saw.
(e) Motion of the hammer of an electric bell.
(f) Motion of a train on a straight bridge.

Answer

a. Oscillatory
b. Straight line
c. Circular
d. Oscillatory
e. Oscillatory
f. Straight line

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