MCQ 11 Mark
Assertion (A): $(p+1)(p-1)\left(p^2+1\right)\left(p^4+1\right)=\left(p^{16}-1\right)$
Reason (R): $(a+b)(a-b)=a^2-b^2$.
Reason (R): $(a+b)(a-b)=a^2-b^2$.
- ABoth Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of Assertion (A).
- BBoth Assertion (A) and Reason (R) are true and Reason (R) is not the correct explanation of Assertion (A).
- CAssertion (A) is true but Reason (R) is false.
- ✓Assertion (A) is false but Reason (R) is true.
Answer
View full question & answer→Correct option: D.
Assertion (A) is false but Reason (R) is true.
(D) Assertion (A) is false but Reason (R) is true.
$
\begin{array}{l}
(p+1)(p-1)\left(p^2+1\right)\left(p^4+1\right) \\
=[(p+1)(p-1)]\left(p^2+1\right)\left(p^4+1\right) \\
=\left[\left(p^2-1\right)\left(p^2+1\right)\right]\left(p^4+1\right)
\end{array}
$
$
\left[\because \quad(a-b)(a+b)=a^2-b^2\right]
$
$\begin{array}{l}=\left[\left(p^2\right)^2-1^2\right]\left(p^4+1\right)=\left(p^4-1\right)\left(p^4+1\right) \\ =\left[\left(p^4\right)^2-1^2\right]=\left(p^8-1\right) .\end{array}$
$
\begin{array}{l}
(p+1)(p-1)\left(p^2+1\right)\left(p^4+1\right) \\
=[(p+1)(p-1)]\left(p^2+1\right)\left(p^4+1\right) \\
=\left[\left(p^2-1\right)\left(p^2+1\right)\right]\left(p^4+1\right)
\end{array}
$
$
\left[\because \quad(a-b)(a+b)=a^2-b^2\right]
$
$\begin{array}{l}=\left[\left(p^2\right)^2-1^2\right]\left(p^4+1\right)=\left(p^4-1\right)\left(p^4+1\right) \\ =\left[\left(p^4\right)^2-1^2\right]=\left(p^8-1\right) .\end{array}$