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Question 14 Marks
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(1) (B) 6 days
Sohan's 1 day's work $=\frac{1}{10}$;
Mohan's 1 day's work $=\frac{1}{15}$.
(Sohan + Mohan)'s 1 day's work $=\frac{1}{10}+\frac{1}{15}=\frac{3+2}{30}=\frac{5}{30}=\frac{1}{6}$.
Hence, Sohan and Mohan together do the work in 6 days.

(2) (C) ₹ 1600 , ₹ 2400
Ratio of shares of Mohan and Sohan = ratio of their 1 day's work
$=\frac{1}{15}: \frac{1}{10}=2: 3$.
So, Mohan's share $=₹\left(4000 \times \frac{2}{5}\right)=₹ 1600 ;$
Sohan's share $=₹\left(4000 \times \frac{3}{5}\right)=₹ 2400$.

(3) (D) $\frac{2}{5}$
Required fraction $=$ Mohan's 6 day's work $=\left(\frac{1}{15} \times 6\right)=\frac{2}{5}$.

(4) (C) 12 days
(Sohan + Mohan)'s 2 day's work $=\left(\frac{1}{10}+\frac{1}{15}\right)=\frac{3+2}{30}$
$=\frac{5}{30}=\frac{1}{6}$.
$\therefore $ total time taken $=(2 \times 6)$ days $=12$ days.
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Question 24 Marks
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Case study (4 Marks) - MATHS STD 8 Questions - Vidyadip