Questions

Case study (4 Marks)

🎯

Test yourself on this topic

3 questions · timed · auto-graded

Question 14 Marks
Read the following text carefully and answer the questions that follow:
There was a circular park in Defence colony at Delhi. For fencing purpose poles $A, B, C$ and $D$ were installed at the circumference of the park.Ram tied wires From $A$ to $B , B$ to $C$ and $C$ to $D , $ and he managed to measure the $\angle A =100^{\circ}$ and $\angle D =80^{\circ}$
Point $O$ in the middle of the park is the center of the circle.
Image
$i.$ Name the quadrilateral $\text{ABCD} .$
$ii$. What is the value of $\angle C$ ?
$iii$. What is the value of $\angle B$.
OR
Write any three properties of cyclic quadrilateral?
Answer
$i. \text{ABCD}$ is cyclic quadrilateral.
A quadrilateral $\text{ABCD}$ is called cyclic if all the four vertices of it lie on a circle.
Here all four vertices $A, B, C$ and $D$ lie on a circle.
$ii$. We know that the sum of both pair of opposite angles of a cyclic quadrilateral is $180^{\circ}$.
$\angle C +\angle A =1800$
$\angle C =1800=1000=800$
$iii$. We know that
The sum of both pair of opposite angles of a cyclic quadrilateral is $180^{\circ}$.
$\angle B +\angle D =1800$
$\angle B=1800=800=1000$
OR
$I$. In a cyclic quadrilateral, all the four vertices of the quadrilateral lie on the circumference of the circle.
$II$. The four sides of the inscribed quadrilateral are the four chords of the circle.
$III$. The sum of a pair of opposite angles is $180^{\circ} \ ($supplementary$)$.
Let $\angle A , \angle B , \angle C$, and $\angle D$ be the four angles of an inscribed quadrilateral.
Then, $\angle A +\angle C =180^{\circ}$ and $\angle B +\angle D =180^{\circ}$.
View full question & answer
Question 24 Marks
Read the following text carefully and answer the questions that follow:
In a forest, a big tree got broken due to heavy rain and wind. Due to this rain the big branches $AB$ and $AC$ with lengths $5 m$ fell down on the ground. Branch $AC$ makes an angle of $30^{\circ}$ with the main tree $AP$. The distance of Point $B$ from $P$ is $4 m$ . You can observe that $\triangle ABP$ is congruent to $\triangle ACP$.
Image
$i.$ Show that $\triangle ACP$ and $\triangle ABP$ are congruent.
$ii$. Find the value of $\angle ACP$ ?
$iii$. Find the value of $\angle BAP$ ?
OR
What is the total height of the tree?
Answer
$i$. In $\triangle ACP$ and $\triangle ABP$
$AB = AC \ ($Given$)$
$AP = AP \ ($common$)$
$\angle APB =\angle APC =90^{\circ}$
By $\text{RHS}$ criteria $\triangle ACP \cong \triangle ABP$
$ii$. In $\triangle ACP$
$\angle APC+\angle PAC+\angle ACP=180^{\circ}$
$\Rightarrow 90^{\circ}+30^{\circ}+\angle ACP=180^{\circ} \text { (angle sum property of } \triangle \text { ) }$
$\Rightarrow \angle ACP=180^{\circ}-120^{\circ}=60^{\circ}$
$\angle ACP=60^{\circ}$
$iii. \triangle ACP \cong \triangle ABP$
Corresponding part of congruent triangle
$\angle BAP =\angle CAP$
$\angle BAP =30^{\circ}\ ($given $ \angle CAP =30^{\circ})$
OR
$\triangle ACP$
$AC ^2= AP ^2+ PC ^2$
$\Rightarrow 25= AP ^2+16$
$\Rightarrow AP ^2=25-16=9$
$\Rightarrow A P=3$
Total height of the tree $= AP + 5 = 3 + 5 = 8 m$
View full question & answer
Question 34 Marks
Answer
i. Let the no of questions whose answer is known to Ajay be x and number questions attempted by guessing be y.
x + y = 110
$x+14 y=80 \Rightarrow 4 x+y=320 x+y=110 \ldots(1)$
4x + y = 320 ...(2)
Solving (1) and (2)
x + y - 4x - y = 110 - 320 = -210
$\Rightarrow-3 x=-210$
$\Rightarrow x=70$
ii. x + y = 110
$x+14 y=80 \Rightarrow 4 x+y=320$
x + y = 110 ...(1)
4x + y = 320 ...(2)
Solving (1) and (2)
x + y - 4x - y = 110 - 320 = - 210
$\Rightarrow-3 x=-210$
$\Rightarrow x=70$
Put x = 70 in (1)
70 + y = 110
$\Rightarrow y=40$
40 question he answered by guessing.
iii. $70-40 \times \frac{1}{4}=70-10=60$ marks
He scored 60 marks.x $-\frac{1}{4}(110-x)=95$
OR
$\Rightarrow 4 x-110+x=380$
$\Rightarrow 5 x=380+110=490$
$\Rightarrow x=\frac{490}{5}=98$
So he answered 98 correct answers 12 by guessing.
View full question & answer