2 Marks Questions

Question 12 Marks

30 children were asked about the number of hours they watched TV programmes last week. The results are recorded as under:

Number of hours	0-5	5-10	10-15	15-20
Frequency	8	16	4	2

Can we say that the number of children who watched TV for 10 or more hours a week is 22? Justify your answer.

Answer

10 is considered in 10 - 15 and not in 5 - 10. So, we cannot say that number of children who watched TV for 10 or more hours a week is 22. In fact, the number of children who watch TV for 10 or more hours a week are 4 + 2 = 6.

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Question 22 Marks

Mean of 50 observations was found to be 80.4. But later on, it was discovered that 96 was misread as 69 at one place. Find the correct mean.

Answer

Mean of 50 students of = 80.4
$\therefore$ Sum of observation = 80.4 × 50 = 4020
As, 96 was misread as 69,
So, the correct total = 4020 - 69 + 96 = 4047
Hence, the correct mean $=\frac{4047}{50}=80.94$

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Question 32 Marks

In a diagnostic test in mathematics given to students, the following marks (out of 100) are recorded:
46, 52, 48, 11, 41, 62, 54, 53, 96, 40, 98, 44
Which ‘average’ will be a good representative of the above data and why?

Answer

Median will be a good representative of the data, because:

Each value occurs once.
The data is influenced by extreme values.

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Question 42 Marks

The class marks of a continuous distribution are:
1.04, 1.14, 1.24, 1.34, 1.44, 1.54 and 1.64
Is it correct to say that the last interval will be 1.55 - 1.73? Justify your answer.

Answer

It is not correct. Because the difference between two consecutive class marks should be equal to the class size. Here, difference between two consecutive marks is 0.1 and class size of 1.55 - 1.73 is 0.18, which are not equal.

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Question 52 Marks

In there is a histogram depicting daily wages of workers in a factory. Construct the frequency distribution table.

Answer

Class interval	Frequency
150-200 200-250 250-300 300-350 350-400	50 30 35 20 10
Total	145

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Question 62 Marks

The points scored by a basket ball team in a series of matches are as follows:
17, 2, 7, 27, 25, 5, 14, 18, 10, 24, 48, 10, 8, 7, 10, 28.
Find the median and mode for the data.

Answer

Arranging the given data in ascending order, we get
2, 5, 7, 7, 8, 10, 10, 14, 17, 18, 24, 25, 27, 28, 48
We find, 10 occurs most frequently i.e., maximum number of times.
There, mode of the data = 10
Here, n = 16(even)

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Maths 2 Marks Questions

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