1 Marks Question

Question 11 Mark

Find the surface area of a sphere of diameter:$3.5\ cm$

Answer

Given Diameter $= 3.5\ cm$
Radius $=\frac{\text{Diameter}}{2}$
$=\frac{3.5}{2}=1.75\text{cm}$
Surface area $4\pi\text{r}^2$
$=4\times\frac{22}{7}\times(1.75)^2$
$=38.5\text{cm}^2$

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Question 21 Mark

Find the volume of a sphere whose radius is: $2\ cm.$

Answer

Radius $(r) = 2cm$
Therefore volume $=\frac{4}{3\pi\text{r}^3}$
$=\frac{4}{3}\times\frac{22}{7}\times(2)^3$
$=33.52\text{cm}^3$

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Question 31 Mark

Find the surface area of a sphere of diameter:$21\ cm$

Answer

Given Diameter $= 21\ cm$ Radius $=\frac{\text{Diameter}}{2}$
$=\frac{21}{2}=10.5\text{cm}$ Surface area $4\pi\text{r}^2$
$=4\times\frac{22}{7}\times(10.5)^2$
$=1386\text{cm}^2$

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Question 41 Mark

Find the volume of a sphere whose radius is:$10.5\ cm.$

Answer

Radius $(r) = 10.5cm$
Therefore volume $=\frac{4}{3\pi\text{r}^3}$
$=\frac{4}{3}\times\frac{22}{7}\times(10.5)^3=4851\text{cm}^2$

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Question 51 Mark

Find the volume of a sphere whose radius is: $3.5\ cm$

Answer

Radius $(r) = 3.5\ cm$ Therefore volume $=\frac{4}{3\pi\text{r}^3}$ $=\frac{4}{3}\times\frac{22}{7}\times(3.5)^3$ $=179.666\text{cm}^3$

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Question 61 Mark

Find the volume of a sphere whose diameter is: $14\ cm.$

Answer

Diameter $= 14\ cm$,
Radius (r) $=\frac{14}{2}=7\text{cm}$
Therefore volume $=\frac{4}{3\pi\text{r}^3}$
$=\frac{4}{3}\times\frac{22}{7}\times(7)^2=1437.33\text{cm}^3$

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Question 71 Mark

Find the surface area of a sphere of radius: $10.5\ cm$

Answer

Given Radius $= 15.5\ cm$
Surface area $=4\pi\text{r}^2$
$=4\times\frac{22}{7}\times(10.5)^2$
$=1386\text{cm}^2$

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Question 81 Mark

Find the surface area of a sphere of radius:$14\ cm$

Answer

Given radius $= 14\ cm$
Surface area $=4\pi\text{r}^2$
$=4\times\frac{22}{7}\times(14)^2$
$=2464\text{cm}^2$

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Question 91 Mark

Find the surface area of a sphere of radius: $5.6\ cm$

Answer

radius Given $= 5.6\ cm$
Surface area $=4\pi\text{r}^2$
$=4\times\frac{22}{7}\times(5.6)^2$
$=394.24\text{cm}^2$

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Question 101 Mark

Find the surface area of a sphere of diameter:
$14\ cm$

Answer

Given Diameter $= 14\ cm$
Radius $=\frac{\text{Diameter}}{2}$
$=\frac{14}{2}=7\text{cm}$
Surface area $=4\pi\text{r}^2$
$=4\times\frac{22}{7}\times(7)^2$
$=616\text{cm}^2$

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Question 111 Mark

Find the volume of a sphere whose diameter is:
$3.5\ dm$

Answer

Diameter $= 3.5\ dm$, Radius $(r) 3.52 = 1.75\ dm$
Therefore volume $=\frac{4}{3\pi\text{r}^3}$
$=\frac{4}{3}\times\frac{22}{7}\times(1.75)^3$
$= 22.46dm^3$

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Question 121 Mark

Find the volume of a sphere whose diameter is:$2.1m$

Answer

Diameter $= 2.1\ m,$
Radius (r) $=\frac{2.1}{2}=1.05\text{m}$
Therefore volume $=\frac{4}{3\pi\text{r}^3}$
$=\frac{4}{3}\times\frac{22}{7}\times(1.05)^3=4.851\text{m}^3$

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Question 131 Mark

If a sphere is inscribed in a cube, find the ratio of the volume of cube to the volume of the sphere.

Answer

$6: \pi$

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Question 141 Mark

The surface area of a sphere of radius 5 cm is five times the area of the curved surface of a cone of radius 4 cm. Find the height of the cone.

Answer

3 cm

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Question 151 Mark

If a hollow sphere of internal and external diameters 4 cm and 8 cm respectively melted into a cone of base diameter 8 cm, then find the height of the cone.

Answer

14 cm

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Question 161 Mark

If a sphere of radius 2r has the same volume as that of a cone with circular base of radius r, then find the height of the cone.

Answer

32r

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Question 171 Mark

How many spherical bullets can be made out of a solid cube of lead whose edge measures 44 cm, each bullet being 4 cm in diameter?

Answer

2541

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Question 181 Mark

Find the volume of a sphere whose surface area is 154 $cm ^2$.

Answer

$179.66 cm^3$

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Question 191 Mark

The hollow sphere, in which the circus motor cyclist performs his stunts, has a diameter of 7 m. Find the area available to the motorcyclist for riding.

Answer

$154 m^2$

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Question 201 Mark

Find the radius of a sphere whose surface area is 154 $cm ^2$.

Answer

3.5 cm

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Question 211 Mark

Find the total surface area of a hemisphere of radius 10 cm.

Answer

942 $cm ^2$.