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Question 11 Mark
It is given thet $\triangle\text{ABC}\cong\triangle\text{RPQ}.$ Is it true to say thet BC = QR? Why?
Answer
It is False that BC = QR becouse BC = PQ as $\triangle\text{ABC}\cong\triangle\text{RPQ}.$
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Question 21 Mark
Is it possible to construct a triangle with lengths of its sides as 9cm, 7cm and 17cm? Give reason for your answer.
Answer
No, it is not possible to construct a triangle whose sides are 9cm, 7cm and 17cm.
Because,
9cm + 7cm = 16cm < 17cm.
Whereas sum of any two sides of a triangle is always greater than the third side.
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Question 31 Mark
In $\triangle\text{ABC}$ and $\triangle\text{PQR},\angle\text{A}=\angle\text{Q}$ and $\angle\text{B}=\angle\text{R}.$ Which side of $\triangle\text{PQR}$ should be equal to side AB of $\triangle\text{ABC},$ so that the two triangles are congruent? Give reason for your answer.
Answer
In triangle ABC and PQR, we have
$\angle\text{A}=\angle\text{Q}$
$\angle\text{B}=\angle\text{R}$
For the triangle to be congruent, we must AB = QR. They will be congruent by ASA rule.
BC = RP
They will be congruent by AAS congruence rule.
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Question 41 Mark
It is given thet $\triangle\text{PQR}\cong\triangle\text{EDF},$ then Is it true to say that PR = EF? Given reason for your answer.
Answer
Yes, PR = FE becouse thry are the correponding sides of $\triangle\text{PQR}$ and $\triangle\text{EDF}.$
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Question 51 Mark
Is it possible to construct a triangle with lengths of its sides as 8cm, 7cm and 4cm? Give reason for your answer.
Answer
Yes, it is possible to construct a triangle with lengths of sides as 8cm, 7cm and 4cm as sum of any two sides of a triangle is greater than the third side.
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