Question 11 Mark
Assertion (A) : The sum of first 9 terms of the GP 3,6,12, $\ldots$ is 1533.
Reason (R) : The sum of first $n$ terms of a GP is given by $S _n=\frac{a\left(r^n-1\right)}{r-1}$.
Reason (R) : The sum of first $n$ terms of a GP is given by $S _n=\frac{a\left(r^n-1\right)}{r-1}$.
Answer
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