MCQ 11 Mark
The angles of depression of two ships from the top of a lighthouse are $45^{\circ}$ and $30^{\circ}$ towards east. If the ships are 100 m apart, the height of the lighthouse is:
- A$\frac{20}{(\sqrt{3}+1)} \mathrm{m}$
- B$\frac{20}{(\sqrt{3}-1)} \mathrm{m}$
- C$50(\sqrt{3}-1) \mathrm{m}$
- D$50(\sqrt{3}+1) \mathrm{m}$
Answer
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