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Question 15 Marks
A two digit number is such that its product of its digit is 18. When 63 is subtracted from the number, the digits interchange their places. Find the number.
Answer
Let this two digit number be XY. Then as per the question,
$X Y=18 \ldots . . \text { (i) }$
$X Y-63=Y X .\ldots(ii)$
Let this two digit number be 'Xi. Which means $X =10 x$ (as it comes in tens digit).
Then as per the question, $x x y=1$ s ... $10 x+y-63=10 y+x$
$\Rightarrow 9 x-9 y-63=0$
$\Rightarrow x-y-7=0$
$\Rightarrow$ Puting $x=\frac{18}{ y }$ in above, we get
$\Rightarrow 18- y ^2-7 y =0$
$\Rightarrow y ^2+7 y -18=0$
$\Rightarrow y^2+9 y-2 y-18=0$
$\Rightarrow( y +2)( y -9)=0$
As y can't be negative, hence $y=9$
$\Rightarrow$ Hence $x=\frac{18}{9}=2($ from (i))
$\Rightarrow$ Hence answer is 92
Alternate Answer:
From (i), possible combinations are: 29, 36, 63, 92.
From (ii), it's clear that the number ' $Xi$ is more than 63 as that is the only case when we subtract this number by 63 , we get a positive value.
Hence, the number is 92 and when we delete it by 63 , we get a number of 29 which is a numbers where the digits are interchanged.
Hence answer is 92.
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Question 25 Marks
The hypotenuse of a right-angled triangle is $17\ cm$. If the smaller side is multiplied by $5$ and the larger side is doubled, the new hypotenuse will be $50 \ cm$. Find the length of each side of the triangle.
Answer
Let hypotenuse=h, and other sides by x and y (x bigger than y). As per the question,
$h = 17 , X^2 + y^2 = 17 X 17$
$\Rightarrow x^2 + y^2 = 289 ..... (i)$
In second scenario, sides become Sy and 2x, new h becomes 50 cm
$\Rightarrow (5y)^2 + (2x)^2 = 50 x 50$
$\Rightarrow 25y^2 + 4x^2= 2500$
$\Rightarrow (21y^2 + 4 y^2 )+ 4x^2 = 2500 ..... (ii)$
Putitng $(i)$ in $(ii)$, we get:
$21y^2 + 4(289) = 2500$
$\Rightarrow 21y^2= 1344$
$\Rightarrow y^2 = 64$
Hence $y = 8cm.$
Putting this is $(i)$, we get
$\Rightarrow x^2= 289 - 64 = 225$
$\Rightarrow x= 25cm$
Hence, the sides are $8, 15, 17 \ cm.$
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[5 marks sum] - Mathematics STD 10 Questions - Vidyadip