Question 11 Mark
Prove that $(x-3)$ is a factor of $x^3 - x^2 - 9x +9$ and hence factorize it completely.
Answer
View full question & answer→If $x - 3$ assumed to be factor, then $x = 3$. Substituting this in problem polynomial, we get:
$f(3) = 3 × 3 × 3 - 3 × 3 - 9 × 3 + 9 = 0$
Hence its proved that $x - 3$ is a factor of the polynomial.
$f(3) = 3 × 3 × 3 - 3 × 3 - 9 × 3 + 9 = 0$
Hence its proved that $x - 3$ is a factor of the polynomial.