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25 questions · timed · auto-graded

Question 12 Marks
25 metres of cloth costs ₹ 1,012.50. How many metres of the same kind can be bought for ₹ 1,620?
Answer
Cost of $25 m$ of cloth = ₹ 1012.50
Cloth purchased by ₹1  $=\frac{25}{1012.5} m$
Cloth purchased by ₹$1620=\frac{25}{1012.5} \times 1620=40$ metres
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Question 22 Marks
25 metres of cloth costs ₹ 1,012.50. What will be the cost of 20 metres of cloth of the same type?
Answer
Cost of $25 m$ of cloth  =  ₹ 1012.50
Cost of $1 m$ of cloth  = ₹ $\frac{1012.50}{25}$
$\therefore$ Cost of $20 m$ of cloth = ₹  $\frac{1012.50}{25} \times 20=$ ₹  810
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Question 32 Marks
If John walks 250 steps to cover a distance of 200 metres, find the distance covered by him in 350 steps
Answer
Distance covered with 250 steps $=200 m$
Distance covered with 1 step $=\frac{200}{250} m$
Distance covered with 350 steps $=\frac{200}{250} \times 350=280 m$
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Question 42 Marks
If a deposit of ₹ 2,000 earns an interest of ₹ 500 in 3 years, how much interest would a deposit of ₹ 36,000 earn in 3 years with the same rate of simple interest?
Answer
Interest earned on deposit of ₹2000 for 3 months =₹ 500
Interest earned on deposit of ₹ 1 for 3 months  = ₹$\frac{500}{2000}$
Interest earned on deposit of ₹ 36000 for 3 months $=$ ₹$\frac{500}{2000} \times 36000$ = ₹ $9000$
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Question 52 Marks
A truck requires 108 litres of diesel for covering a distance of 1188 km. How much diesel will be required by the truck to cover a distance of 3300 km?
Answer
Diesel required to cover a distance of $1188 km =108$ litres
Diesel required to cover a distance of $1 km =\frac{108}{1188}$ litres
Diesel required to cover a distance of $3300 km =\frac{108}{1188} \times 3300$ litres $=300$ litres
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Question 62 Marks
Mr. Chopra pays ₹ 12,000 as rent for 3 months. How much does he has to pay for a year if the rent per month remains same?
Answer
Rent for 3 months = ₹ 12000
Rent for 1 month  = ₹ $\frac{12000}{3}$
Rent for 1year (or 12 months)
= ₹ $\frac{12000}{3} \times 12$ = ₹48000
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Question 72 Marks
The temperature dropped 18 degree Celsius in the last 24 days. If the rate of temperature drop remains the same, how many degrees will the temperature drop in the next 18 days?
Answer
The temperature drop in the last 24 days $=18^{\circ} C$
The temperature drop in the last 1 day $=\frac{18^{\circ} C }{24}$
The temperature drop in the last 18 day $=\frac{248^{\circ} C }{24} \times 18=13.5^{\circ} C$
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Question 82 Marks
Geeta types 108 words in 6 minutes. How many words would she type in half an hour?
Answer
Words typed by Geeta in 6 minutes $=108$
Words typed by Geeta in 1 minute $=\frac{108}{6}$
Words typed by Geeta in half-hour or 30 minutes $=\frac{108}{6} \times 30=540$ words
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Question 92 Marks
Weight of 15 books is 6 kg. What is the weight of 45 such books?
Answer
Weight of 15 books $=6 kg$
Weight of 1 book $=\frac{6}{15} kg$
Weight of 45 such books $=\frac{15}{6} \times 45=112.5 kg$
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Question 102 Marks
A car covers a distance of 180 km in 5 hours. How much time will the car take to cover 54 km with the same speed?
Answer
To cover a distance of $180 km$, time taken $=5$ hours
To cover a distance of $1 km$, time taken $=\frac{5}{180}$
To cover a distance of $54 km$, time taken $=\frac{5}{180} \times 54=1.5$ hours
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Question 112 Marks
A car covers a distance of 180 km in 5 hours. How much distance will the car cover in 3 hours with the same speed?
Answer
Distance covered by car $180 km$ in 5 hours
Distance covered in 1 hour $=\frac{180}{5}=36 km$
Distance covered in 3 hours $=3 \times 36=108 km$
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Question 122 Marks
If the cost of a dozen identical articles is ₹ 672, what will be the cost of 18 such articles?
Answer
Cost of one dozen articles=₹ 672
Cost of one article = ₹ $\frac{672}{12}$ = ₹ 56
Cost of 18 articles =₹ $56 \times 18$=₹ 1008
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Question 132 Marks
A motorbike travels 425 km in 5 hours. How much distance will be covered by it in 3.2 hours?
Answer
Distance covered by motorbike $=425 km$
Time taken $=5$ hours
Distance covered by motorbike in 1 hour $=\frac{425}{5} km / hr =85 km / hr$
Then, distance covered in 3.2 hours $=85 \times 3.2=272 km / hr$
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Question 142 Marks
For ₹ 378, 9 cans of juice can be bought, then how many cans of juice can be bought for ₹ 504?
Answer
In ₹ 378 , the juice can be bought $=9$ cans
In  ₹ 504 , the cans of juice will be bought $=\frac{9}{378}$
12 cans of juice can be bought in ₹ 504 .
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Question 152 Marks
If the cost of 8 cans of juice is ₹ 280, then what will be the cost of 6 cans of juice?
Answer
Cost of 8 cans of juice = ₹280
Cost of 1 can of juice $=\frac{280}{8}$ = ₹35
then, cost of 6 cans of juice $=6 \times$ ₹35 = ₹210 
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Question 162 Marks
The cost of 35 envelops is ₹ 105. How many envelops can be bought for ₹ 90?
Answer
Envelops purchased by  ₹ 105 = 35
Envelopes purchased by ₹ $1=\frac{35}{105}$
In ₹ 90 , the envelop will be bought $=\frac{35}{105} \times 90=30$
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Question 172 Marks
If the cost of a dozen soaps is ₹ 460.80, what will the cost of 3 dozen soaps?
Answer
Cost of one dozen soap= ₹ 460.80
In one dozen $=12$ soaps
Cost of each soap  = ₹ $\frac{460.80}{12}$= ₹  38.4
Cost of 3 dozen soaps $=(12 \times 3=36)=36 \times $ ₹ 38.4 = ₹ 1382.4
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Question 182 Marks
If the cost of a dozen soaps is ₹ 460.80, what will the cost of 15 soaps?
Answer
Cost of one dozen soap =₹$460.80$
In one dozen $=12$ soaps
Cost of each soap =₹$\frac{460.80}{12}$ = ₹38.4
Cost of 15 soaps $=15 \times$ ₹38.4 = ₹576 
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Question 192 Marks
If the cost of a dozen soaps is ₹ 460.80, what will the cost of each soap?
Answer
Cost of one dozen soap = ₹ 460.80
In one dozen $=12$ soaps
Cost of each soap = ₹  $\frac{460.80}{12}=$ ₹ 38.4 
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Question 202 Marks
A motorbike travels 330 km in 5 litres of petrol. How much distance will it cover in 2.5 litres of petrol?
Answer
Consuming 5 litres petrol in $30 km$
Consuming 1 litre petrol, motorbike covers $=\frac{330}{5} km =66 km$
Consuming 2.5 litres petrol $=66 \times 2.5=165 km$
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Question 212 Marks
A loaded truck travels 18 km in 25 minutes. If the speed remains the same, how far can it travel in 5 hours?
Answer
A loaded truck travels in 25 minutes a distance of $=18 km$
A loaded truck travels in $1 min$ a distance of $=\frac{18}{25} km$
A loaded truck travels in shows or 300 minutes, a distance of $=\frac{18}{25} \times 300=216 km$
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Question 222 Marks
A tree 24 m high casts a shadow of 15 m. At the same time, the length of the shadow casted by some other tree is 6 m. Find the height of the tree.
Answer
Height of a tree which casts a shadow of $15 m =24 m$
Height of a tree which casts a shadow 24 of $1 m =\frac{24}{15} m$
Height of a tree which casts a shadow of $6 m =\frac{24}{15} \times 6=9.6 m$
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Question 232 Marks
The price of 25 identical articles is ₹1,750. Find the price of 13 articles
Answer
The price of 25 articles  = ₹ 1,750
Price of one article  = ₹ $\frac{1750}{25}=$ ₹ 70
Now, Price of 13 articles $=13$ x ₹ 70= ₹ 910 
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Question 242 Marks
Cost of 10 kg of wheat is ₹ 180. What is the cost of 18 kg of wheat?
Answer
Cost of $10 kg$ wheat  = ₹ 180
Cost of $1 kg$ of wheat =₹$\frac{180}{10}$ = ₹ 18
$\therefore$ cose of $18 kg$ of wheat   =18 x ₹ 18 = ₹ 324
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Question 252 Marks
If it has rained 276 cm in the last 3 days, how many cm of rain will fall in one week (7 days)?
Assume that the rain continues to fall at the same rate.
Answer
Rate of rainfall in 3 days $=276 cm$
Rainfall in one day $=\frac{276}{3}=92 cm$
Rainfall in one week $=92 \times 7=644 cm$
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[2 Mark Question Answer] - MATHS STD 6 Questions - Vidyadip