MCQ

MCQ 11 Mark

In a school, only 2 out of 5 students can participate in a quiz. What is the probability that a student picked at random makes it to the competition?

A
$50 \%$
B
$40 \%$
C
$30 \%$
D
$20 \%$

Answer

In a school, 2 out of 5 students can participate in a quiz Probability of 2 students picked at random $=\frac{2}{5}$ $=\frac{2}{5} \times 100=40 \%$ (b)

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MCQ 21 Mark

A bag contains 5 white balls and 10 black balls. The probability of drawing a white ball from the bag is

A
$\frac{5}{10}$
B
$\frac{5}{15}$
C
$\frac{10}{15}$
D
1

Answer

A bag contains 5 white and 10 black balls.
Total balls in the bag $=5+10=15$
Probability of drawing a white ball $=\frac{5}{15}=\frac{1}{3}$ (b)

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MCQ 31 Mark

When a die is thrown, the probability of getting a composite number is

A
$\frac{1}{2}$
B
$\frac{1}{3}$
C
$\frac{1}{4}$
D
$\frac{2}{3}$

Answer

When a die is thrown, probability of a composite number $(4,6)=\frac{2}{6}=\frac{1}{3}$ (b)

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MCQ 41 Mark

The probability of selecting a vowel from the word ALPHABET is

A
$\frac{1}{2}$
B
$\frac{1}{7}$
C
$\frac{2}{7}$
D
$\frac{3}{8}$

Answer

The probability of selecting a vowel from the word ALPHABET (Vowels are A, A, E) $=\frac{3}{8}(d)$

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MCQ 51 Mark

The probability of selecting letter G from the word GIRL is

A
1
B
$\frac{1}{2}$
C
$\frac{1}{4}$
D
$\frac{1}{3}$

Answer

Probability of letter G from the word GIRL is $\frac{1}{4}$. (c)

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MCQ 61 Mark

The probability of a newly born baby to be a girl is

A
$0$
B
$\frac{1}{4}$
C
$\frac{1}{2}$
D
1

Answer

The probability of a newly bom baby to be a girl is $\frac{1}{2}$. $\text{(c)}$

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MCQ 71 Mark

The probability of an impossible event is

A
$-1$
B
$0$
C
$\frac{1}{2}$
D
1

Answer

The probability of an impossible event is 0. (b)

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MCQ 81 Mark

The probability of a sure event is

A
$0$
B
$\frac{1}{4}$
C
$\frac{1}{2}$
D
1

Answer

The probability of a sure event is 1 . (d)

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MCQ 91 Mark

The mode of the data : 3, 5, 1, 2, 0, 2, 3, 5, 0, 2, 1, 6 is

Answer

Mode of 3, 5, 1, 2, 0, 2, 3, 5, 0, 2, 1, 6 = 2
as it came highest times $\text{(c)}$

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MCQ 101 Mark

The mean of three different natural numbers is 40. If lowest is 19, what could be highest possible number of remaining two numbers?

A
40
B
71
C
81
D
100

Answer

The mean of three different natural numbers = 40
Lowest = 19, then highest possible of the remaining two numbers
Total = 40 × 3 = 120
Lowest = 19
Remaining total = 120 – 19 = 101
Both of the remaining numbers are greater than 19
So, if second is 20, then third = 101 – 20 = 81
Highest = number = 81 $\text{(c)}$

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MCQ 111 Mark

The median of the first 49 natural numbers is

A
24
B
25
C
25.5
D
26

Answer

Median of first 49 natural number (i.e., 1 to 99 ) $=\frac{49+1}{2}=25$ th term $=25(b)$

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MCQ 121 Mark

The number of goals scored by a football team in a series of matches are: 3, 5, 0, 1, 2, 0, 4, 1, 3. The median of this data is

A
3
B
2
C
2.5
D
1

Answer

Goals in the matches are:
$3,5,0,1,2,0,4,1,3$
Arranging in order: $0,0,1,1,2,3,4,5$
Which are 9 which is odd
$\text { median }=\frac{9+1}{2}=5 \text { th term }=2(b)$

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MCQ 131 Mark

If the mean of $3, 1, 5, x$ and $9$ is $4,$ then the value of $x$ is