MCQ 11 Mark
In the given figure, PA || BC || DQ and AB || DC. Then the values of x and y are respectively :


- A50°, 120°
- B50°, 130°
- C60°, 120°
- D60°, 130°
Answer
View full question & answer→In the given figure,
PA || BC || DQ
AB || DC
x = 50° (Alternate angles)
∠BCD + ∠ABC = 180° (Sum of co-interior angles)
⇒ ∠DCB + 50° = 180°
⇒ ∠DCB = 180° – 50° = 130°
BC || DQ
∠DCB = ∠CDQ (Alternate angles)
y = 130°
x = 50°, y = 130° (b)
PA || BC || DQ
AB || DC
x = 50° (Alternate angles)
∠BCD + ∠ABC = 180° (Sum of co-interior angles)
⇒ ∠DCB + 50° = 180°
⇒ ∠DCB = 180° – 50° = 130°
BC || DQ
∠DCB = ∠CDQ (Alternate angles)
y = 130°
x = 50°, y = 130° (b)



