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6 questions · timed · auto-graded

Question 12 Marks
Find the rate percent if the S.I. on ₹275 is 2 years is ₹22.
Answer
$ \text { Principal }(P)=$₹ 275 , S.I. = ₹ 22
Time $=2$ years
$ \begin{aligned} & \therefore \text { Rate }=\frac{\text { S.I. } \times 100}{\mathrm{P} \times \mathrm{T}} \\ & =\frac{22 \times 100}{275 \times 2}=4 \% \text { p.a. } \end{aligned} $
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Question 22 Marks
The simple interest earned on a certain sum in 5 years is 30% of the sum. Find the rate of interest.
Answer
Let the sum $(P)=$ ₹ 100
S.I. $=\frac{30}{100} \times$ ₹ 100= ₹ 30
Period $(T)=5$ years
$ \therefore \text { Rate }=\frac{\text { S.I. } \times 100}{\mathrm{P} \times \mathrm{T}}=\frac{30 \times 100}{100 \times 5}=6 \% $
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Question 32 Marks
A sum of money is lent for 5 years at R% simple interest per annum. If the interest earned be one-fourth of the money lent, find the value of R.
Answer
Let the $\operatorname{sum}(P)=$₹ 100
$ \therefore \text { S.I. }=\frac{1}{4} $ x ₹ 100 = ₹ 25
Period $(T)=5$ years
$\therefore$ Rate $\%=\frac{\text { S.I. } \times 100}{\mathrm{P} \times \mathrm{T}}$
$ \frac{25 \times 100}{100 \times 5}=5 \% $
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Question 42 Marks
Find the S.I. and amount on Rs. 620 for 4 months at 8 p. per rupee per month.
Answer
$ P=\text { Rs. } 620, R=8 \text { p. per rupee per month }=8 \% \text { p.m.. } $
$\mathrm{T}=4$ months
$ \therefore \text { S.I. }=\frac{\text { P.R.T }}{100}=\frac{620 \times 8 \times 4}{100}=\text { Rs. } \frac{19840}{100}=\text { Rs. } 198.40 $
and amount $=\mathrm{P}+\mathrm{S} . \mathrm{I}$.
$ =\text { Rs. } 620+\text { Rs. } 198.40=\text { Rs. } 818.40 $
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Question 52 Marks
Find the S.I. and amount on Rs. 350 for $3 \frac{1}{2}$ years at $8 \%$ p.a.
Answer
$P=$ Rs. $350, R=8 \%$ p.a. $T=3 \frac{1}{2}$ years $=\frac{7}{2}$ years
$ \therefore \text { S.I. }=\frac{\text { P.R.T }}{100}=\frac{350 \times 8 \times 7}{100 \times 2}=\text { Rs. } 98 $
and amount $=\mathrm{P}+\mathrm{S} . \mathrm{I}$.
$ =\text { Rs. } 350+\text { Rs. } 98=\text { Rs. } 448 $
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Question 62 Marks
Find the S.I. and amount on Rs. 150 for 4 years at 5% per year.
Answer

$\begin{aligned} & \text { P }=\text { Rs. } 150, R=5 \% \text { per year } T=4 \text { years } \\ & \therefore \text { S.I. }=\frac{\text { P.R.T }}{100}=\frac{150 \times 5 \times 4}{100}=\text { Rs. } 30 \\ & \text { and amount }=P+\text { S.I. } \\ & =\text { Rs. } 150+\text { Rs. } 30=\text { Rs. } 180\end{aligned}$
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[2 Mark Question Answer] - MATHS STD 7 Questions - Vidyadip