Question 15 Marks
A sum of $₹ 500$ is in the form of notes of denominations of $₹ 5$ and $₹ 10.$ If the total number of notes is $90,$ find the number of notes of each type.
Answer
View full question & answer→Let the number of $₹ 5$ notes $=x$
$\therefore$ The number of $\text₹ 10$ notes $=90-x$
Value of $₹ 10$ notes = $x \times ₹5 = ₹ 3 x$
and value of $₹ 10$ notes $== (90-x) x ₹10 = (900 - 10x)$
$\therefore$ Total value of all the notes $=₹ 500$
$\therefore 5 x+(900-10 x)=500$
$\Rightarrow 5 x+900-10 x=500 $
$\Rightarrow-5 x=500-900$
$ \Rightarrow x=\frac{400}{5}$
$\Rightarrow x=80$
$\therefore$ The number of $₹ 5$ notes $= x = 80$
and the number of $₹10$ notes $= 90 - X$
$= 90 - 80 =10$
$\therefore$ The number of $\text₹ 10$ notes $=90-x$
Value of $₹ 10$ notes = $x \times ₹5 = ₹ 3 x$
and value of $₹ 10$ notes $== (90-x) x ₹10 = (900 - 10x)$
$\therefore$ Total value of all the notes $=₹ 500$
$\therefore 5 x+(900-10 x)=500$
$\Rightarrow 5 x+900-10 x=500 $
$\Rightarrow-5 x=500-900$
$ \Rightarrow x=\frac{400}{5}$
$\Rightarrow x=80$
$\therefore$ The number of $₹ 5$ notes $= x = 80$
and the number of $₹10$ notes $= 90 - X$
$= 90 - 80 =10$