MATHS [2 Mark Question Answer]

We know that the sum of three angles of a triangle is 180°, therefore
In figure,
a + 90° + 40° = 180°
⇒ a + 130° = 180°
⇒ a = 180° − 130° = 50°
Hence a = 50°

We know that the sum of three angles of a triangle is 180°, therefore
In figure,
y + 80° + 20° = 180°
⇒ y + 100° = 180°
⇒ y = 180° − 100° = 80°
Hence y = 80°

We know that the sum of three angles of a triangle is 180°, therefore
In figure,
90° + 30° + x = 180°
⇒ 120° + x = 180°
⇒ x = 180° − 120° = 60°
Hence x = 60°

Since the sum of angles of a triangle is 180°
∴ ∠A + ∠B + ∠C = 180°
⇒ 45° + 75° + ∠C = 180°
⇒ 120° + ∠C = 180°
⇒ ∠C = 180° − 120° = 60°

We know that the sum of three angles of a triangle is 180°, therefore
Sum of 125°, 40°, and 15°
= 125° + 40° + 15° = 180°
Since the sum is 180°, therefore it is possible.

We know that the sum of three angles of a triangle is 180°, therefore
Sum of 60°, 60°, and 50°
= 60° + 60° + 50° = 170°
Since the sum is not 180°, therefore it is not possible.

We know that in a triangle if one side of it is produced, then
Exterior angle = sum of its interior opposite angles.
In fig., 135° = a° + 73°
⇒ a° = 135°− 73° = 62°

We know that in a triangle if one side of it is produced, then
Exterior angle = sum of its interior opposite angles.
In fig., 122° = k° + 35°
⇒ k° = 122°− 35° = 87°

We know that in a triangle if one side of it is produced, then
Exterior angle = sum of its interior opposite angles.
In fig., 120° = y° + 60°
⇒ y° = 120°− 60° = 60°

We know that in a triangle if one side of it is produced, then
Exterior angle = sum of its interior opposite angles.
In fig., 110° = x° + 30°
⇒ x° = 110°− 30° = 80°

We know that the sum of three angles of a triangle is 180°, therefore
Sum of 40°, 130°, and 20°
= 40° + 130° + 20° = 190°
Since the sum is not 180°, therefore it is not possible.

We know that the sum of three angles of a triangle is 180°, therefore
Sum of 20°, 70°, and 90°
= 20° + 70° + 90° = 180°
Since the sum is 180°. Hence it is possible.