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Question 13 Marks
A rectangular piece of wood measures $4 \ cm$ by $6 \ cm$ by $8 \ cm$ and has a mass of $20 g.$ What is the density of the piece of wood ?
Answer
Volume of the piece of wood $=(4 \times 6 \times 8) \ cm ^3=192 \ cm ^3$
Mass of the piece $=20 g$
Density $=\frac{\text { Mass }}{\text { Volume }}$
$\frac{20 g }{192 \ cm ^3}=0,104 g \ cm ^{-3}$
Relative density of wood
$=\frac{\text { Density of wood }}{\text { Density of water at } 4^{\circ} C }$
$=\frac{0.104 g / \ cm ^3}{1 g / \ cm ^3}$
$=0.104$
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Question 23 Marks
Explain how you would measure the area of an irregular shape using a graph paper.
Answer
Irregular shapes do not have easily measurable dimensions. However, we can indirectly find the area of an irregular surface using a graph paper. Place a leaf on a graph paper and trace its outline with the help of a pencil. Remove the leaf. Now count the number of complete squares within the outline.
Also count the number of incomplete squares that are half or more than half within the outline. Ignore the number of squares that are less than half. The area of the leaf $= ($Number of complete squares$) \ cm^2 + ($Number of half or more-than-half squares$) \ cm^2$.
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[3 Mark Question Answer] - PHYSICS STD 7 Questions - Vidyadip