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4 questions · timed · auto-graded

Question 12 Marks
A girl applies a force of 60 N in pushing a table, such that work done by her is 15 J. Calculate the displacement produced in the table.
Answer
Given,
Work done = 15 J
Force applied = 60 N
Therefore,
Work done= Force × Displacement
15=60 × Displacement
Displacement= 15/60​
Displacement = 0.25 m
The displacement produced in the table is 0.25 m.
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Question 22 Marks
A body does a work 0f 1000 J in dragging a sack of rice through a distance of 20 m. What is the magnitude of force applied by the boy ?
Answer
Work done= Force × Displacement
Given,
Work done = 1000 J
Displacement = 10m
Therefore,
Work done= Force × Displacement
1000=Force×20
Force=201000​
Force=50N
The magnitude of force applied by the boy is 50 N.
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Question 32 Marks
A force of 15 N causes a displacement of 5 m in its own direction. What is the magnitude of work done?
Answer
Work done = Force × Displacement
Given, Force = 15 N
Displacement = 5 m
Therefore,
Work done = 15×5 = 75 J
The work done is 75 Joule.
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Question 42 Marks
The SI unit of work or energy is joule. Explain why the work and energy have same SI unit.
Answer
The SI unit o f work or energy is joule and they have same SI unit because energy is the form of work that is stored and work is the one that is used. Therefore, work and energy, while not synonyms, are consistent with respect to the object. So they both have the same SI unit.
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[2 Mark Question Answer] - PHYSICS STD 7 Questions - Vidyadip