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Question 14 Marks
Differentiate between an efflorescent, deliquescent $\&$ hygroscopic substance with suitable examples.
Answer
Efflorescent substances:
$(i)$ Lose wholly or partially their water of crystallisation when exposed to air.
$(ii)$ Become powdery.
$(iii)$ Washing soda $\ce{CaCO_3 \cdot 10 H_2O}$, Gauber's salt $\ce{Na_2SO_4 \cdot 10 H_2O}$, epsom salt $\ce{MgSO_47H_2O}$
$\ce{Na_2CO \cdot 10H_2O \xrightarrow{\text { dry air }} Na_2CO_3 \cdot H_2O + 9 H_2O}$
$(iv)$ Crystalline when hydrated.
Deliquescent substances:
$(i)$ Absorb moisture from atmosphere, absorb water and dissolve in it forming a saturated solution.
$(ii)$ Deliquescence is maximized in dry conditions.
$(iii)\ce{ NaOH , KOH , CaCl _2, MgCl _2, FeCl _3}$ are the examples.
$(iv)$ They are crystalline water soluble.
$\ce{FeCl _3 \longrightarrow FeCl _3}$
Crystal changes to Solution
Hygroscopic substances:
$(i)$ They are amorphous solids or liquids.
$(ii)$ Absorb moisture from the air of atmosphere.
$(iii)$ Do not change their original state.
$\ce{CaO}($quick lime$)$, cone. $\ce{H_2 SO_4, P_2O_5}$ and silica gel are the examples.
$\underset{\text { Conc. }}{ \ce{H_2 SO_4}} \longrightarrow \underset{\text { Conc. }}{\ce{H_2SO_4}} \quad$ $($State not changed$)$
is used for drying gases in laboratory.
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Question 24 Marks
Differentiate between ‘hydrated’ & ‘anhydrous’ crystals. Give the chemical formula of $–$ the following hydrated crystals$-$
$(a)$ Washing soda
$(b)$ Gypsum
$(c)$ Blue vitriol
$(d)$ Epsom salt
$(e)$ Glauber’s salt. State which crystal from
$(a)$ to $(e)$ is a pentahydrate.
Answer
Hydrated crystals : Contain definite number of water molecules - in loose chemical combination with the crystals. Anhydrous crystals : Do not contain any definite number of water molecules - in loose chemical combination with the crystals.
Formula of hydrated crystals :
$(a)$ Washing soda : $\ce{CaCO_310H_2O}$
$(b)$ Gypsum : $\ce{CaSO_4 \cdot 2H_2O}$
$(c)$ Blue vitriol: $\ce{CuSO_45H_2O}$
$(d)$ Epsom salt: $\ce{MgSO_2 \cdot 7 H_2O}$
$(e)$ blue vitriol $[\ce{CuSO_4 \cdot 5 H_2O]}$ is a pentahydrate.
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[5 Mark Question Answer] - CHEMISTRY STD 8 Questions - Vidyadip