MCQ 11 Mark
If the area of a rectangle is $24\left(x^2 y z+x y^2 z+x y z^2\right)$ and its length is $8\ x y z$, then its breadth is
- ✓$3(x+y+z)$
- B$3\ x y z$
- C$3(x+y-z)$
- Dnone of these
Answer
View full question & answer→Correct option: A.
$3(x+y+z)$
In a rectangle
Area $=24\left(x^2 y z+x y^2 z+x y z^2\right)$
Length $=8 x y z$
Breadth $=\frac{24 x y z(x+y+z)}{8 x y z}=3( x + y + z )$
Area $=24\left(x^2 y z+x y^2 z+x y z^2\right)$
Length $=8 x y z$
Breadth $=\frac{24 x y z(x+y+z)}{8 x y z}=3( x + y + z )$