MCQ 11 Mark
Probability of getting a non-red ball from a bag containing $4$ red, $5$ blue and $3$ black balls is
- A$\frac{1}{3}$
- ✓$\frac{2}{3}$
- C$\frac{1}{4}$
- D$\frac{5}{12}$
Answer
View full question & answer→Correct option: B.
$\frac{2}{3}$
In a bag, there are $4$ red balls, $5$ blue and $3$ black balls.
$\therefore$ Total outcomes $=4+5+3=12$
Probability of a non$-$red ball $( 5$ blue $+3$ black$) =8$
$=\frac{8}{12}=\frac{2}{3}$
$\therefore$ Total outcomes $=4+5+3=12$
Probability of a non$-$red ball $( 5$ blue $+3$ black$) =8$
$=\frac{8}{12}=\frac{2}{3}$