Question 11 Mark
If $ξ = \{$all digits in our number system$\}, A = \{$multiples of $2\}$ and $B = \{$multiples of $3\}$, then $A ∩ B = \{6\}.$
Answer
View full question & answer→If $ξ = \{$all digits in our number system$\}, A = \{$multiples of $2\}$
and $B = \{$multiples of $3\}$, then $A ∩ B = \{6\}. ($True$)$
If $ξ = \{$all digits in our number system$\}$
$= \{0, 1, 2, 3, 4, 5, 6, 7, 8, 9\}$
$A = \{$multiples of $2\} = \{2, 4, 6, 8\}$
$B = \{$multiples of $3\} = \{3, 6, 9\}$
Then $A ∩ B = \{6\}$
and $B = \{$multiples of $3\}$, then $A ∩ B = \{6\}. ($True$)$
If $ξ = \{$all digits in our number system$\}$
$= \{0, 1, 2, 3, 4, 5, 6, 7, 8, 9\}$
$A = \{$multiples of $2\} = \{2, 4, 6, 8\}$
$B = \{$multiples of $3\} = \{3, 6, 9\}$
Then $A ∩ B = \{6\}$