Question 13 Marks
Insert three rational numbers between $10$ and $12$
Answer$10$ and $12$
Given numbers $=10$ and $12$
$=10, \frac{10+12}{2}, 12$
$ =10,11,12$
$ =10, \frac{10+11}{2}, 11, \frac{11+12}{2}, 2$
$ =10,10.5,11,11.5,12$
Required rational numbers between $10$ and $12$ are $=10.5,11,11.5$
View full question & answer→Question 23 Marks
Insert three rational numbers between $3$ and $4$
Answer$3$ and $4$
Given numbers $=3$ and 4
$=3, \frac{3+4}{2}, 4$
$=3,3.5,4$
$=3, \frac{3+3.5}{2}, 3.5, \frac{3.5+4}{2}, 4$
$=3,3.25,3.5,3.75,4$
required rational numbers between $3$ and $4$ are $=3.25,3.5$ and $3.75$
View full question & answer→Question 33 Marks
Insert two rational numbers between $2.7$ and $6.3$
Answer$2.7$ and $6.3$
Given numbers $=2.7$ and $6.3$
$=2.7, \frac{2.7+6.3}{2}, 6.3$
$ =2.7,4.5,6.3$
$ =2.7,4.5, \frac{4.5+6.3}{2}, 4.5,6.3$
$ =2.7,4.5,5.4,6.3$
View full question & answer→Question 43 Marks
Insert two rational numbers between $4.8$ and $6$
Answer$4.8$ and $6$
Given numbers $=4.8$ and $6$
$=4.8, \frac{4.8+6}{2}, 6$
$ =4.8,5.4,6$
$($Insert one rational number and $6)$
$=4.8, \frac{4.8+5.4}{2}, 5.4,6$
$ =4.8,5.1,5.4,6$
$\therefore$ Required rationalnumbers between $4.8$ and $6$ are $=5.1$ and $5.4$
View full question & answer→Question 53 Marks
Insert two rational numbers between $6$ and $7$
Answer$6$ and $7$
Given numbers $=6$ and $7$
$=6, \frac{6+7}{2}, 7$
$($Inserting one rational number between $6$ and $7)$
$=6, \frac{13}{2}, 7$
$=6,6.5,7$
$=6, \frac{6+6.5}{2}, 6.5,7$
$=6,6.25,6.5,7 A$
View full question & answer→Question 63 Marks
Cost of $3 \frac{2}{5}$ metre of cloth is $₹ 88 \frac{1}{2}$. what is the cost of $1$ metre of cloth?
AnswerGiven, cost of $3 \frac{2}{5}$ or $\frac{17}{5}$ metre cloth or
$= \text {₹} 88 \frac{1}{2}= \text {₹} \frac{177}{2}$
$\therefore$ Cost of one metre cloth $=\frac{177}{2} \div \frac{17}{5}$
$=\frac{177}{2} \times \frac{5}{17}= \text {₹} \frac{885}{34}= \text {₹} 26 \frac{1}{34}$
View full question & answer→Question 73 Marks
By what number must $\frac{-3}{4}$ be multiplied so that the product is $\frac{-9}{16} ?$
Answer$\therefore$ The product of two number is $=-\frac{9}{16}$
And, one of them is $=-\frac{3}{4}$
$\therefore$ The other number $=\frac{-9}{16} \div\left(-\frac{3}{4}\right)$
$=-\frac{9}{16} \times\left(-\frac{4}{3}\right)$
$=\frac{3 \times 1}{4 \times 1}$
$=\frac{3}{4}$
View full question & answer→Question 83 Marks
$m$ and $n$ are two rational number such that $m \times n =-\frac{25}{9}$ if $n =-\frac{10}{9}$, find $m$
Answer$ \therefore m \times n =-\frac{25}{9}$
$ n =-\frac{10}{9}$
$ m \times-\frac{10}{9}=\frac{-25}{9}$
$ m =\frac{-25}{9} \times \frac{9}{-10}$
$ m =\frac{5 \times 1}{1 \times 2}=\frac{5}{2}=2 \frac{1}{2}$
View full question & answer→Question 93 Marks
$m$ and $n$ are two rational number such that $m \times n =-\frac{25}{9}$ if $m =\frac{5}{3}$, find $n$.
Answer$ \therefore m \times n =-\frac{25}{9}$
$ m =\frac{5}{3}$
$ \therefore \frac{5}{3} \times n =\frac{-25}{9}$
$ n =\frac{-25}{9} \times \frac{3}{5}$
$ n =\frac{-5 \times 1}{3 \times 1}=\frac{-5}{3}$
View full question & answer→Question 103 Marks
The product of two numbers is $\frac{-4}{9}$. If one of them is $\frac{-2}{27}$, find the other.
Answer$\therefore$ The product of two numbers is $=-\frac{4}{9}$
And, one of them is $=\frac{-2}{27}$
$\therefore$ The other number $=-\frac{4}{9} \div\left(\frac{-2}{27}\right)$
$=-\frac{4}{9} \times \frac{27}{-2}$
$=\frac{2 \times 3}{1 \times 1}=6$
View full question & answer→Question 113 Marks
The product of two rational numbers is $-2 $. If one of them is $\frac{4}{7}$, find the other.
Answer$\therefore$ The Product of two numbers is $=-2$
And, one of them is $\frac{4}{7}$
$\therefore$ The other number $=-2 \div \frac{4}{7}$
$=-2 \times \frac{7}{4}$
$ =\frac{-1 \times 7}{1 \times 2}$
$=\frac{-7}{2}$
View full question & answer→Question 123 Marks
The product of two rational numbers is $-5$ . If one of these numbers is $\frac{-7}{15}$, find the other.
AnswerLet the required rational number be $= x$
Other number $=\frac{-7}{15}$
Product of rational numbers $=-5$
$\Rightarrow \frac{-7}{15} \times x =-5$
$ \Rightarrow-7 x =-5 \times 15$
$ \Rightarrow x =\frac{-75}{-7}=\frac{75}{7}$
View full question & answer→Question 133 Marks
Divide the sum of $\frac{3}{7}$ and $\frac{-5}{14}$ by $\frac{-1}{2}$
Answer$\left[\frac{3}{7}+\left(\frac{-5}{14}\right)\right] \div \frac{-1}{2}$
$\therefore \text{LCM}$ of $7$ and $14=14$
$=\left[\frac{3}{7} \times \frac{2}{2}-\frac{5}{14}\right] \div \frac{-1}{2}$
$ =\left[\frac{6-5}{14}\right] \div \frac{-1}{2}$
$ =\frac{1}{14} \times \frac{-2}{1}$
$ =\frac{1 \times(-1)}{7 \times 1}$
$=\frac{-1}{7}$
View full question & answer→Question 143 Marks
For the pair of rational numbers, given below, verify that the multiplication is commutative. $ 0$ and $\frac{-12}{17}$
Answer$=0 \times \frac{-12}{17}$
$=\frac{0 \times(-12)}{1 \times 17}=0$ And $\frac{-12}{17} \times 0$
$=\frac{(-12) \times 0}{17 \times 1}=0$
$\therefore 0 \times \frac{-12}{17}=\frac{-12}{17} \times 0$
View full question & answer→Question 153 Marks
For the pair of rational numbers, given below, verify that the multiplication is commutative. $\frac{5}{-3}$ and $\frac{13}{-11}$
Answer$=\frac{5}{-3} \times \frac{13}{-11}$
$=\frac{5 \times 13}{(-3) \times(-11)}=\frac{65}{33}$ And, $\frac{13}{-11} \times \frac{5}{-3}$
$=\frac{13 \times 5}{(-3) \times(-11)}=\frac{65}{33}$
$ \therefore \frac{5}{-3} \times \frac{13}{-11}=\frac{13}{-11} \times \frac{5}{-3}$
View full question & answer→Question 163 Marks
Evaluate: $\left(-5 \times \frac{2}{15}\right)-\left(-6 \times \frac{2}{9}\right)$
Answer$ =\frac{(-5) \times 2}{1 \times 15}-\frac{(-6) \times 2}{1 \times 9}$
$ =\frac{(-1) \times 2}{1 \times 3}-\frac{(-2) \times 2}{1 \times 3}$
$ =\frac{-2}{3}-\left(\frac{-4}{3}\right)$
$ =\frac{-2+4}{3}$
$=\frac{2}{3}$
View full question & answer→Question 173 Marks
Evaluate: $\left(2 \times \frac{1}{4}\right)-\left(\frac{-18}{7} \times \frac{-7}{15}\right)$
Answer$ =\left(\frac{2 \times 1}{1 \times 4}\right)-\left(\frac{(-18) \times(-7)}{7 \times 15}\right)$
$ =\left(\frac{1 \times 1}{1 \times 2}\right)-\left(\frac{(-18) \times(-1)}{1 \times 15}\right)$
$ =\frac{1}{2}-\frac{18}{15}$
| $2$ |
$2, 15$ |
| $3$ |
$1, 15$ |
| $5$ |
$1, 5$ |
|
$1, 1$ |
$\text{LCM}$ of $2 $ and $15$ is $2 \times 3 \times 5=30$
$=\frac{1 \times 15}{2 \times 15}-\frac{18 \times 2}{15 \times 2}$
$\text{LCM}$ of $2$ and $15=30$
$=\frac{15-36}{30}=\frac{-21}{30}=\frac{-7}{10}$ View full question & answer→Question 183 Marks
What should be added to $-2$ to get $\frac{3}{8}$ ?
AnswerLet the required number be $=x$
According to the question,
$-2+ x =\frac{3}{8}$
$ \Rightarrow x =\frac{3}{8}+2$
$ \Rightarrow x =\frac{3+16}{8}=\frac{19}{8}=2 \frac{3}{8}$
$\therefore$ The required number $=\frac{19}{8}=2 \frac{3}{8}$
View full question & answer→Question 193 Marks
What should be subtracted from $-2$ to get $\frac{3}{8}$ ?
AnswerSet the required number be $=x$
According to the condition,
$-2-x=\frac{3}{8}$
$ \Rightarrow-x=\frac{3}{8}+2$
$ \Rightarrow-x=\frac{3+16}{8}$
$ \Rightarrow x =\frac{-19}{8}$
$\therefore$ The required number $=\frac{-19}{8}$
View full question & answer→Question 203 Marks
Which rational number should be subtracted from $\frac{5}{6}$ to get $\frac{4}{9}$ ?
AnswerRequired rational number $=\frac{-5}{6}-\frac{4}{9}$
| $2$ |
$6, 9$ |
| $3$ |
$3,9$ |
| $3$ |
$1, 3$ |
|
$1, 1$ |
$\therefore \text{LCM}$ of $6$ and $9=18$
$=\frac{-5 \times 3}{6 \times 3}-\frac{4 \times 2}{9 \times 2} \quad(\therefore\text{ LCM}$ of $6$ and $9=18)$
$=\frac{-15}{18}-\frac{8}{18}$
$=\frac{-15-8}{18}$
$=\frac{-23}{18}$
$=-1 \frac{5}{18}$ View full question & answer→Question 213 Marks
Which rational number should be added to $\frac{-5}{9}$ to get $\frac{-2}{3}$ ?
AnswerRequired rational number
$=\frac{-2}{3}-\left(\frac{-5}{9}\right)$
$ =\frac{-2}{3}+\frac{5}{9}$
| $3$ |
$3, 9$ |
| $3$ |
$1, 3$ |
|
$1, 1$ |
$\text{LCM}$ of $3$ and $9=9$
$=\frac{-2 \times 3}{3 \times 3}+\frac{5 \times 1}{9 \times 1}$
$\text{LCM}$ of $3$ and $9=9$
$=\frac{-6+5}{9}=\frac{-1}{9}$ View full question & answer→Question 223 Marks
The sum of the two rational numbers is $-6$ , If one of them is $\frac{-8}{5}$, Find the other.
AnswerThe sum of two rational numbers $=-6$
And, one of the numbers $=\frac{-8}{5}$
The other rational number
$=\frac{-6}{1}-\frac{-8}{5}$
$ =\frac{-6 \times 5}{1 \times 5}+\frac{8 \times 1}{5 \times 1}$
$ =\frac{-30+8}{5}=\frac{-22}{5}$
View full question & answer→Question 233 Marks
Subtract: $\frac{-9}{22}$ from $\frac{5}{33}$
Answer$\frac{-9}{22}$ from $\frac{5}{33}$
| $2$ |
$22, 33$ |
| $3$ |
$11, 33$ |
| $11$ |
$1, 11$ |
| |
$1,1$ |
$\therefore \text{LCM}$ of $22$ and $33=2 \times 3 \times 11=66$
$=\frac{5}{33}-\left(\frac{-9}{22}\right)$
$ =\frac{5 \times 2}{33 \times 2}+\frac{9 \times 3}{22 \times 3} \quad(\therefore \text { LCM}$ of $22$ and $33=66)$
$ =\frac{10+27}{66}=\frac{37}{66}$ View full question & answer→Question 243 Marks
Subtract: $\frac{-5}{8} \text { from } \frac{-13}{16}$
Answer$\frac{-5}{8}$ from $\frac{-13}{16}$
| $2$ |
$8, 16$ |
| $2$ |
$4, 8$ |
| $2$ |
$2, 4$ |
| $2$ |
$1, 2$ |
|
$1, 1$ |
$\therefore \text{LCM}$ of $8$ and $16=16$
$=\frac{-13}{16}-\left(\frac{-5}{8}\right)$
$ =\frac{-13 \times 1}{16 \times 1}+\frac{5 \times 2}{8 \times 2} \quad(\therefore \text { LCM of } 8 \text { and } 16=16)$
$ =\frac{-13+10}{16}=\frac{-3}{16}$ View full question & answer→Question 253 Marks
Subtract: $\frac{1}{4} \text { from } \frac{-3}{8}$
Answer$\frac{1}{4}$ from $\frac{-3}{8}$
| $2$ |
$4, 8$ |
| $2$ |
$2, 4$ |
| $2$ |
$1, 2$ |
|
$1, 1$ |
$\therefore \text { LCM of } 4,8=2 \times 2 \times 2=8$
$=\frac{-3}{8}-\frac{1}{4}(\therefore \text{LCM}$ of $8$ and $4=8)$
$=\frac{-3 \times 1}{8 \times 1}-\frac{1 \times 2}{4 \times 2}$
$ =\frac{-3-2}{8}=\frac{-5}{8}$ View full question & answer→Question 263 Marks
Evaluate: $\frac{5}{21}-\frac{-13}{42}$
Answer
| $2$ |
$21, 42$ |
| $3$ |
$21, 21$ |
| $7$ |
$7, 7$ |
| |
$1, 1$ |
$\text{LCM}$ of $21,42$
$=2 \times 3 \times 7=42$
$=\frac{5 \times 2}{21 \times 2}-\frac{-13 \times 1}{42 \times 1}$
$\text{LCM}$ of $21$ and $42=42 )$
$=\frac{10+13}{42}=\frac{23}{42}$ View full question & answer→Question 273 Marks
Evaluate: $\frac{-5}{18}-\frac{-2}{9}$
Answer
| $2$ |
$18, 9$ |
| $3$ |
$9, 9$ |
| $3$ |
$3, 3$ |
|
$1, 1$ |
$\therefore \text{LCM}$ of $9$ and $18$
$=2 \times 3 \times 3=18$
$\therefore \frac{-5}{18}-\frac{-2}{9}$
$ =\frac{-5 \times 1}{18 \times 1}-\frac{-2 \times 2}{9 \times 2}$
$ =\frac{-5+4}{18}$
$ =\frac{-1}{18}$ View full question & answer→Question 283 Marks
Evaluate: $\frac{2}{3}+\frac{-4}{5}-\frac{1}{3}-\frac{2}{5}$
Answer$ \frac{2}{3}+\frac{-4}{5}-\frac{1}{3}-\frac{2}{5}$
$ \Rightarrow\left(\frac{2}{3}-\frac{1}{3}\right)+\left(\frac{-4}{5}-\frac{2}{5}\right)$
$ \Rightarrow \frac{1}{3}+\frac{-6}{5}$
$ \Rightarrow \frac{1}{3}-\frac{6}{5}$
$ \Rightarrow \frac{(1 \times 5)-(6 \times 3)}{15}(\therefore \text { LCM of } 3 \text { and } 5=15)$
$ \Rightarrow \frac{5-18}{15} \Rightarrow-\frac{13}{15}$
View full question & answer→Question 293 Marks
Evaluate: $\frac{3}{7}+\frac{-4}{9}-\frac{-11}{7}-\frac{7}{9}$
Answer$ \frac{3}{7}+\frac{-4}{9}-\frac{-11}{7}-\frac{7}{9}$
$ \Rightarrow\left(\frac{3}{7}-\frac{-11}{7}\right)+\left(\frac{-4}{9}-\frac{7}{9}\right)$
$ \Rightarrow\left(\frac{3}{7}+\frac{11}{7}\right)+\left(\frac{-4}{9}-\frac{7}{9}\right)$
$ \Rightarrow \frac{14}{7}+\frac{-11}{9}$
$ \Rightarrow 2-\frac{-11}{9}$
$ \Rightarrow \frac{2 \times 9-11}{9}$
$\Rightarrow \frac{18-11}{9} $
$\Rightarrow \frac{7}{9}$
View full question & answer→Question 303 Marks
Evaluate: $\frac{4}{7}+0+\frac{-8}{9}+\frac{-13}{7}+\frac{17}{9}$
Answer$\frac{4}{7}+\frac{-8}{9}+\frac{-13}{7}+\frac{17}{9}$
$ =\left[\frac{4}{7}+\left(\frac{-13}{7}\right)\right]+\left(\frac{-8}{9}+\frac{17}{9}\right)$
$ =\left(\frac{4}{7}\right)-\frac{13}{7}+\frac{-8}{9}+\frac{17}{9}$
$ =\frac{-9}{7}+\frac{9}{9}=\frac{-9}{7}+1$
$ =\frac{-9 \times 1}{7 \times 1}+\frac{1 \times 7}{1 \times 7}$
$(\text{LCM}$ of $1$ and $7=7 )$
$=\frac{-9}{7}+\frac{7}{7}=\frac{-2}{7}$
View full question & answer→Question 313 Marks
Evaluate: $\frac{2}{3}+\frac{-4}{5}+\frac{1}{3}+\frac{2}{5}$
Answer$ \left(\frac{2}{3}+\frac{1}{3}\right)+\left(\frac{-4}{5}+\frac{2}{5}\right)$
$ =\frac{2+1}{3}+\frac{-4+2}{5}$
$ =\frac{3}{3}+\left(\frac{-2}{5}\right)$
| $3$ |
$3, 5$ |
| $5$ |
$1, 5$ |
|
$1, 1$ |
$\text{LCM}$ of $3$ and $5=3 \times 5=15$
$=\frac{3 \times 5}{3 \times 5}+\frac{-2 \times 3}{5 \times 3}$
$\text{LCM}$ of $3$ and $5=15$
$=\frac{15-6}{15}=\frac{9}{15}=\frac{3}{5}$ View full question & answer→Question 323 Marks
Evaluate: $\frac{3}{7}+\frac{-4}{9}+\frac{-11}{7}+\frac{7}{9}$
Answer$ =\left(\frac{3}{7}+\frac{-11}{7}\right)+\left(\frac{-4}{9}+\frac{7}{9}\right)$
$ =\frac{3-11}{7}+\frac{-4+7}{9}$
$ =\frac{-8}{7}+\frac{3}{9}$
| $7$ |
$7, 9$ |
| $3$ |
$1,9$ |
| $3$ |
$1,3$ |
|
$1,1$ |
$ =\frac{-72+21}{63}$
$ =\frac{-51}{63}$
$ =\frac{-17}{21}$ View full question & answer→Question 333 Marks
Evaluate: $\frac{-8}{9}+-\frac{5}{12}$
Answer$\frac{-8}{9}+-\frac{5}{12}$
| $2$ |
$9, 12$ |
| $2$ |
$9, 6$ |
| $3$ |
$9, 3$ |
| $3$ |
$3, 1$ |
|
$1, 1$ |
$\text{LCM}$ of $9,12$
$=2 \times 2 \times 3 \times 3=36$
$=\frac{-8 \times 4}{9 \times 4}-\frac{5 \times 3}{12 \times 3}$
$ =\frac{-32-15}{36} \quad(\text { LCM of } 9 \text { and } 12=36)$
$ =\frac{-47}{36}$ View full question & answer→Question 343 Marks
Evaluate: $\frac{5}{9}+\frac{3}{-4}$
Answer$\frac{5}{9}-\frac{3}{4}$
| $2$ |
$9, 4$ |
| $2$ |
$9, 2$ |
| $3$ |
$9, 1$ |
| $3$ |
$3, 1$ |
|
$1,1$ |
$(\text{LCM}$ of $9$ and $4=2 \times 2 \times 3 \times 3=36)$
$=\frac{5 \times 4}{9 \times 4}-\frac{3 \times 9}{4 \times 9}$
$ =\frac{20-27}{36}=\frac{-7}{36}$
$\text{(LCM}$ of $9$ and $4=36 )$
$=\frac{-7}{36}$ View full question & answer→Question 353 Marks
Evaluate: $\frac{1}{-15}+\frac{5}{-12}$
Answer$ \frac{1}{-15}+\left(\frac{5}{-12}\right)$
$ =\frac{-1}{15}-\frac{5}{12}$
| $2$ |
$15, 12$ |
| $2$ |
$15, 6$ |
| $3$ |
$15, 3$ |
| $5$ |
$5, 1$ |
|
$1, 1$ |
$\text{LCM}$ of $15$ and $12$
$=2 \times 2 \times 3 \times 5=60$
$\frac{-1 \times 4}{15 \times 4}-\frac{5 \times 5}{12 \times 5} \ldots(\because \text{LCM}$ of $15$ and $12=$ $60)$
$=\frac{-4-25}{60}$
$=\frac{-29}{60}$ View full question & answer→Question 363 Marks
Evaluate: $\frac{5}{9}+\frac{-7}{6}$
Answer$\frac{5}{9}+\frac{-7}{6}$
| $2$ |
$9, 6$ |
| $3$ |
$9, 3$ |
| $3$ |
$3, 1$ |
|
$1, 1$ |
$\text{LCM}$ of $9$ and $6=2 \times 3 \times 3=18$
$=\frac{5 \times 2}{9 \times 2}-\frac{7 \times 3}{6 \times 3}$
$\text{(LCM}$ of $9$ and $6=18 )$
$=\frac{10-21}{18}$
$ =\frac{-11}{18}$ View full question & answer→Question 373 Marks
Add, the pair of rational numbers, given below, and show that their addition $($sum$)$ is also a rational number
$\frac{7}{-18}$ and $\frac{8}{27}$
Answer$ \frac{7}{-18}+\frac{8}{27}$
$ =\frac{-7 \times 3}{18 \times 3}+\frac{8 \times 2}{27 \times 2}$
| $2$ |
$18, 27$ |
| $3$ |
$9, 27$ |
| $3$ |
$3, 9$ |
| $3$ |
$1, 3$ |
|
$1, 1$ |
$\text{LCM}$ of $18$ and $27=2 \times 3 \times 3 \times 3=54$
$=\frac{-21+16}{54}=-\frac{5}{54}$
Which is a rational number. View full question & answer→Question 383 Marks
Add, the pair of rational numbers, given below, and show that their addition $($sum$)$ is also a rational number$\frac{9}{-4} \text { and } \frac{-3}{8}$
Answer$\frac{9}{-4}+\frac{-3}{8}$
| $2$ |
$4, 8$ |
| $2$ |
$2, 4$ |
| $2$ |
$2, 2$ |
|
$1, 1$ |
$\text{LCM}$ of $4$ and $8=2 \times 2 \times 2=8$
$=\frac{-9 \times 2}{4 \times 2}-\frac{3 \times 1}{8 \times 1}$
$( \text{LCM}$ of $4$ and $8=8)$
$=\frac{-18-3}{8}=\frac{-21}{8}$
Which is a rational number View full question & answer→Question 393 Marks
Add, the pair of rational numbers, given below, and show that their addition $($sum$)$ is also a rational number $\frac{5}{-6}$ and $\frac{2}{3}$
Answer$\frac{5}{-6}+\frac{2}{3}$
| $2$ |
$6, 3$ |
| $3$ |
$3, 3$ |
|
$1, 1$ |
$\text{LCM}$ of $6,3=2 \times 3=6$
$=\frac{-5 \times 1}{6 \times 1}+\frac{2 \times 2}{3 \times 2}$
$\text{(LCM}$ of $6$ and $3=6 )$
$=\frac{-5+4}{6}=\frac{-1}{6}$
Which is rational number. View full question & answer→Question 403 Marks
Add, the pair of rational numbers, given below, and show that their addition $($sum$)$ is also a rational number $\frac{5}{-26} \text { and } \frac{8}{39}$
Answer$ \frac{5}{-26}+\frac{8}{39}$
$ =\frac{-5 \times 3}{26 \times 3}+\frac{8 \times 2}{39 \times 2}$
| $2$ |
$26, 39$ |
| $3$ |
$13, 39$ |
| $13$ |
$13, 13$ |
|
$1, 1$ |
$\therefore \text{LCM}$ of $26$ and $39$
$=2 \times 3 \times 13=78$
$=\frac{-15+16}{78}( \text{LCM}$ of $26$ and $39=78)$
$=\frac{1}{78}$
Which is a rational number. View full question & answer→Question 413 Marks
Add, the pair of rational numbers, given below, and show that their addition $($sum$)$ is also a rational number $\frac{-5}{8}$ and $\frac{3}{8}$
Answer$\frac{-5}{8}$ and $\frac{3}{8}$
$ =\frac{-5}{8}+\frac{3}{8}$
$($Denominators are same, $\text{LCM} =8)$
$=\frac{-5+3}{8}$
$ =\frac{-2}{8}=\frac{-1}{4}$
Which is rational number
View full question & answer→