[5 marks sum]

Question 15 Marks

Three years ago, the population of a city was 50000. If the annual increase during three successive years be 5%, 8% and 10% respectively, find the present population of the city.

Answer

62370

View full question & answer→

Question 25 Marks

A town has 15625 inhabitants. If the population of this town increases at the rate of 4% per annum, find the number of inhabitants of the town at the end of 3 years.

Answer

17576

View full question & answer→

Question 35 Marks

The difference between the compound interest for 1 year, compounded half-yearly and the simple interest for 1 year on a certain sum of money at 10% per annum is ₹360. Find the sum.

Answer

144000

View full question & answer→

Question 45 Marks

The difference between the simple interest and the compound interest on a sum of money for 3 years at 10% per annum is ₹558. Find the sum.

Answer

18000

View full question & answer→

Question 55 Marks

Case Study : In 2015, the population of a town was 20000. During 2016 and 2017, it increases by 4% and 5% every year respectively. In 2018, due to an epidemic and migration to cities, the population decreases at 5%.
Based on the above information answer the following questions:
Q.1. The population of the town in 2016 was:
(a) 20800 (b) 20500 (c) 20460 (d) 20300
Q.2. The difference in the population of the town at the end of the years 2017 and 2015 was:
(a) 1500 (b) 1700 (e) 1800 (d) 1840
Q.3. The population of the town at the end of the year 2018 was:
(a) 20100 (b) 20500 (c) 20748 (d) 20850
Q.4. Which of the following expressions gives the population at the end of the year 2018?
(a) $20000 \quad \frac{104}{100} \quad \frac{105}{100} \quad \frac{105}{100}$
(b) $20000 \quad \frac{104}{100} \quad \frac{105}{100} \quad \frac{95}{100}$
(c) $20000 \quad \frac{104}{100} \quad \frac{95}{100} \quad \frac{95}{100}$
(d) $20000 \quad \frac{96}{100} \quad \frac{95}{100} \quad \frac{95}{100}$
Q.5. If the population of the town at the end of 2019 was 21163, then during 2019, the population increases at the rate of:
(a) 2% (b) 3% (c) 3.5% (d) 4%

Answer

1. (a) 2. (d) 3. (c) 4. (b) 5. (a)

View full question & answer→

Question 65 Marks

Case Study : In 2015, the population of a town was 20000. During 2016 and 2017, it increases by 4% and 5% every year respectively. In 2018, due to an epidemic and migration to cities, the population decreases at 5%. Based on the above information answer the following questions:
1. The population of the town in 2016 was:
(a) 20800 (b) 20500 (c) 20460 (d) 20300
The difference in the population of the town at the end of the years 2017 and 2015 was:
(a) 1500 (b) 1700 (c) 1800 (d) 1840
The population of the town at the end of the year 2018 was:
(a) 20100 (b) 20500 (c) 20748 (d) 20850
Which of the following expressions gives the population at the end of the year 2018?
(a) $20000 \times \frac{104}{100} \times \frac{105}{100} \times \frac{105}{100}$
(b) $20000 \times \frac{104}{100} \times \frac{105}{100} \times \frac{95}{100}$
(c) $20000 \times \frac{104}{100} \times \frac{95}{100} \times \frac{95}{100}$
(d) $20000 \times \frac{96}{100} \times \frac{95}{100} \times \frac{95}{100}$
If the population of the town at the end of 2019 was 21163, then during 2019, the population increases at the rate of:
(a) 2% (b) 3% (c) 3.5% (d) 4%

Answer

(1. a), (2. d), (3. c ), (4. b), (5. a)

View full question & answer→

Question 75 Marks

The count of bacteria in a culture grows by 10% during first hour, decreases by 8% during second hour and again increases by 12% during third hour. If the count of bacteria in the sample is 13125000, what will be the count of bacteria after 3 hours?

Answer

14876400

View full question & answer→

Question 85 Marks

Three years ago, the population of a city was 50000. If the annual increase during three successive years be 5%, 8% and 10% respectively, find the present population of the city.

Answer

62370

View full question & answer→

Question 95 Marks

A town has 15625 inhabitants. If the population of this town increases at the rate of 4% per annum, find the number of inhabitants of the town at the end of 3 years.

Answer

17576

View full question & answer→

Question 105 Marks

The difference between the compound interest for 1 year, compounded half-yearly and the simple interest for 1 year on a certain sum of money at 10% per annum is ₹ 360. Find the sum.

Answer

₹ 144000

View full question & answer→

Question 115 Marks

Calculate the amount and the compound interest on ₹ 25000 for 3 years, the rates of interest for the successive years being 8%, 9% and 10%, compounded annually.

Answer

Amount = ₹ 32373, C.I. = ₹ 7373

View full question & answer→

Question 125 Marks

Sudhakar borrows ₹ 22500 at 10% per annum, compounded annually. If he repays ₹ 11250 at the end of first year and ₹ 12550 at the end of the second year, find the amount of loan outstanding against him at the end of the third year.

Answer

₹ 2530

View full question & answer→

MATHEMATICS [5 marks sum]

Test yourself on this topic