[2 Mark Question Answer]

Question 12 Marks

Find the height of a parallelogram whose area is $144\ cm^2$ and the base is $18\ cm.$

Answer

Let the height of the parallelogram $=h$
Area of a parallelogram with base $b$ and height $h$ is $A=b \times h$
$\therefore$ Area of a parallelogram with base $18 \ cm$ and height $h \ cm$ is $A=18\ cm =144 \ cm ^2$
$\Rightarrow h =\frac{144}{18} $
$=8 \ cm .$

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Question 22 Marks

The area of a square is $36\ cm^2$. How long are its sides?

Answer

Area of a square $=36 \ cm ^2$
$\Rightarrow($Side$)^2=36 \ cm ^2$
$\Rightarrow$ Side $=\sqrt{36} \ cm$
$\Rightarrow$ Side $=6 \ cm$
Hence, the length of each side is $6 \ cm$.

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Question 32 Marks

Two adjacent sides of a parallelogram are $34 \ cm$ and $20 \ cm$. If one of its diagonal is $42 \ cm,$ find$:$ distance between its shorter sides.

Answer

Again, area of parallelogram $=$ Base $\times$ Height
$\Rightarrow 672=20 \times $ Height
$\Rightarrow$ Height
$=\frac{672}{20}$
$=33.6 \ cm$
Thus, the distance between the shortest sides of a parallelogram is $33.6 \ cm$.

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Question 42 Marks

The side of a square is of length $20\ mm.$ Find its perimeter in $\ cm.$

Answer

Side of a square $ =20\ mm $
$\therefore $ Perimeter of square
$ =4 \times$ Side
$=4 \times 20\ mm$
$=80\ mm $
$=\frac{80}{10}\ cm $
$=8\ cm .$

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Question 52 Marks

Find the area of an equilateral triangle of side $20\ cm.$

Answer

Side of an equilateral triangle $=20 \ cm$
Area of a triangle
$=\frac{\sqrt{3}}{4} \times($ side $)^2$
$=\frac{\sqrt{3}}{4} \times 20 \times 20 $
$=100 \sqrt{3} \ cm ^2 .$

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MATHEMATICS [2 Mark Question Answer]

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