MCQ 11 Mark
When written in decimal form, which of the following will be a non-terminating and non-repeating number?
- A
$1^{1 / 9}$
- ✓
$2^{1 / 9}$
- C
$2^{-9}$
- D
$9^{1 / 2}$
AnswerCorrect option: B. $2^{1 / 9}$
View full question & answer→MCQ 21 Mark
$1 . \overline{9}-1.9$ is equal to :
View full question & answer→MCQ 31 Mark
$\sqrt[4]{\sqrt[3]{3^2}}$ can be expressed as :
- A
$3^6$
- B
$6^{1 / 3}$
- C
$3^{1 / 12}$
- ✓
$3^{1 / 6}$
AnswerCorrect option: D. $3^{1 / 6}$
View full question & answer→MCQ 41 Mark
$0.6+0 . \overline{7}+0.4 \overline{7}$ is equal to :
- A
$\frac{155}{90}$
- B
$\frac{147}{90}$
- ✓
$\frac{167}{90}$
- D
AnswerCorrect option: C. $\frac{167}{90}$
View full question & answer→MCQ 51 Mark
Four rational numbers $p, q, r$ and $s$ are such that $q$ is the reciprocal of $p$ and $s$ is the reciprocal of $r$. The value of the expression
$\left\{\left(p+\frac{1}{q}\right) \div\left(r+\frac{1}{s}\right)\right\} \quad\left\{\left(s+\frac{1}{r}\right) \quad\left(q+\frac{1}{p}\right)\right\}$ is equal to:
View full question & answer→MCQ 61 Mark
The sum of all rational numbers between 0 and 0.1 is :
View full question & answer→MCQ 71 Mark
Assertion (A) : Each of the numbers $\sqrt[3]{2}, \sqrt[3]{3}, \sqrt[3]{4}, \sqrt[3]{5}, \sqrt[3]{6}, \sqrt[3]{7}$ is irrational.
Reason (R) : The cube roots of all natural numbers is irrational.
View full question & answer→MCQ 81 Mark
Assertion (A) : The number obtained on rationalising the denominator of $\frac{1}{\sqrt{5}-2}$ is $2+\sqrt{5}$.
Reason (R) : If the product of two irrational numbers is rational, then each one is called the rationalising factor of the other.
View full question & answer→MCQ 91 Mark
What is the pure surd for $5 \sqrt[3]{2}$ ?
- A
$\sqrt[3]{125}$
- B
$\sqrt[3]{150}$
- ✓
$\sqrt[3]{250}$
- D
$\sqrt[3]{1000}$
AnswerCorrect option: C. $\sqrt[3]{250}$
View full question & answer→MCQ 101 Mark
The mixed surd for $\sqrt[3]{432}$ is :
- A
$2 \sqrt[3]{6}$
- ✓
$6 \sqrt[3]{2}$
- C
$3 \sqrt[3]{6}$
- D
$6 \sqrt[3]{3}$
AnswerCorrect option: B. $6 \sqrt[3]{2}$
View full question & answer→MCQ 111 Mark
The correct ascending order of $\sqrt{3}, \sqrt[3]{6}, \sqrt[4]{7}$ is :
- A
$\sqrt[3]{6}, \sqrt[4]{7}, \sqrt{3}$
- ✓
$\sqrt[4]{7}, \sqrt{3}, \sqrt[3]{6}$
- C
$\sqrt{3}, \sqrt[4]{7}, \sqrt[3]{6}$
- D
$\sqrt[3]{6}, \sqrt{3}, \sqrt[4]{7}$
AnswerCorrect option: B. $\sqrt[4]{7}, \sqrt{3}, \sqrt[3]{6}$
View full question & answer→MCQ 121 Mark
Two rational numbers between $-\frac{3}{7}$ and $-\frac{1}{7}$ are :
- A
$\frac{4}{14}, \frac{3}{14}$
- B
$-\frac{4}{14}, \frac{3}{14}$
- C
$\frac{4}{14},-\frac{3}{14}$
- ✓
$-\frac{4}{14},-\frac{3}{14}$
AnswerCorrect option: D. $-\frac{4}{14},-\frac{3}{14}$
View full question & answer→MCQ 131 Mark
If $x=5+2 \sqrt{6}$, then $x^2+\frac{1}{x^2}=$
View full question & answer→MCQ 141 Mark
If $x=2-\sqrt{2}$, then $x \quad \frac{1}{x}=$
- A
- B
- C
$2 \sqrt{2}$
- ✓
$2 \sqrt{2}$
AnswerCorrect option: D. $2 \sqrt{2}$
View full question & answer→MCQ 151 Mark
If $x=3+2 \sqrt{2}$, then $x+\frac{1}{x}=$
- A
$4 \sqrt{2}$
- B
$6 \sqrt{2}$
- ✓
- D
View full question & answer→MCQ 161 Mark
The number which is to be subtracted from $\sqrt{72}$ to get $\sqrt{32}$ is :
- A
$2 \sqrt{10}$
- B
$4 \sqrt{2}$
- C
$3 \sqrt{2}$
- ✓
$2 \sqrt{2}$
AnswerCorrect option: D. $2 \sqrt{2}$
View full question & answer→MCQ 171 Mark
Only by inspecting the prime factors of the denominators, state which of the following fractions will be a recurring decimal?
- A
$\frac{7}{16}$
- ✓
$\frac{8}{51}$
- C
$\frac{3}{25}$
- D
$\frac{11}{20}$
AnswerCorrect option: B. $\frac{8}{51}$
View full question & answer→MCQ 181 Mark
Only by inspecting the prime factors of the denominator, state which of the following fractions will be a terminating decimal?
- A
$\frac{7}{12}$
- B
$\frac{2}{15}$
- ✓
$\frac{3}{16}$
- D
$\frac{4}{21}$
AnswerCorrect option: C. $\frac{3}{16}$
View full question & answer→MCQ 191 Mark
0.3 when expressed as a ratio of two integers, becomes :
- ✓
$\frac{103}{330}$
- B
$\frac{52}{165}$
- C
$\frac{103}{111}$
- D
$\frac{104}{333}$
AnswerCorrect option: A. $\frac{103}{330}$
View full question & answer→MCQ 201 Mark
When $8 . \overline{32}$ is expressed as a vulgar fraction, then it becomes:
- A
$\frac{208}{824}$
- ✓
$\frac{824}{99}$
- C
$\frac{800}{99}$
- D
$\frac{416}{45}$
AnswerCorrect option: B. $\frac{824}{99}$
View full question & answer→MCQ 211 Mark
Which of the following is a prime number?
View full question & answer→MCQ 221 Mark
Which of the following is an irrational number?
- A
- B
$2.7 \overline{2}$
- ✓
$\sqrt{11}$
- D
$\frac{2}{7}$
AnswerCorrect option: C. $\sqrt{11}$
View full question & answer→MCQ 231 Mark
Which of the following is a rational number?
- A
$\pi$
- B
$\sqrt{2}$
- ✓
- D
$1.010010001 \ldots$
View full question & answer→MCQ 241 Mark
What is the pure surd for $5 \sqrt[3]{2}$ ?
- A
$\sqrt[3]{125}$
- B
$\sqrt[3]{150}$
- ✓
$\sqrt[3]{250}$
- D
$\sqrt[3]{1000}$
AnswerCorrect option: C. $\sqrt[3]{250}$
View full question & answer→MCQ 251 Mark
The mixed surd for $\sqrt[3]{432}$ is :
- A
$2 \sqrt[3]{6}$
- ✓
$6 \sqrt[3]{2}$
- C
$3 \sqrt[3]{6}$
- D
$6 \sqrt[3]{3}$
AnswerCorrect option: B. $6 \sqrt[3]{2}$
View full question & answer→MCQ 261 Mark
The correct ascending order of $\sqrt{3}, \sqrt[3]{6}, \sqrt[4]{7}$ is :
- A
$\sqrt[3]{6}, \sqrt[4]{7}, \sqrt{3}$
- ✓
$\sqrt[4]{7}, \sqrt{3}, \sqrt[3]{6}$
- C
$\sqrt{3}, \sqrt[4]{7}, \sqrt[3]{6}$
- D
$\sqrt[3]{6}, \sqrt{3}, \sqrt[4]{7}$
AnswerCorrect option: B. $\sqrt[4]{7}, \sqrt{3}, \sqrt[3]{6}$
View full question & answer→MCQ 271 Mark
Two rational numbers between $-\frac{3}{7}$ and $-\frac{1}{7}$ are :
- A
$\frac{4}{14}, \frac{3}{14}$
- B
$-\frac{4}{14}, \frac{3}{14}$
- C
$\frac{4}{14},-\frac{3}{14}$
- ✓
$-\frac{4}{14},-\frac{3}{14}$
AnswerCorrect option: D. $-\frac{4}{14},-\frac{3}{14}$
View full question & answer→MCQ 281 Mark
If $x=5+2 \sqrt{6}$, then $x^2+\frac{1}{x^2}=$
View full question & answer→MCQ 291 Mark
If $x=2-\sqrt{2}$, then $x-\frac{1}{x}=$
- A
- B
- C
$2 \sqrt{2}$
- ✓
$-2 \sqrt{2}$
AnswerCorrect option: D. $-2 \sqrt{2}$
View full question & answer→MCQ 301 Mark
If $x=3+2 \sqrt{2}$, then $x+\frac{1}{x}=$
- A
$4 \sqrt{2}$
- B
$6 \sqrt{2}$
- ✓
- D
View full question & answer→MCQ 311 Mark
The number which is to be subtracted from $\sqrt{72}$ to get $\sqrt{32}$ is :
- A
$2 \sqrt{10}$
- B
$4 \sqrt{2}$
- C
$3 \sqrt{2}$
- ✓
$2 \sqrt{2}$
AnswerCorrect option: D. $2 \sqrt{2}$
View full question & answer→MCQ 321 Mark
Only by inspecting the prime factors of the denominators, state which of the following fractions will be a recurring decimal?
- A
$\frac{7}{16}$
- ✓
$\frac{8}{51}$
- C
$\frac{3}{25}$
- D
$\frac{11}{20}$
AnswerCorrect option: B. $\frac{8}{51}$
View full question & answer→MCQ 331 Mark
Only by inspecting the prime factors of the denominator, state which of the following fractions will be a terminating decimal?
- A
$\frac{7}{12}$
- B
$\frac{2}{15}$
- ✓
$\frac{3}{16}$
- D
$\frac{4}{21}$
AnswerCorrect option: C. $\frac{3}{16}$
View full question & answer→MCQ 341 Mark
0.3 when expressed as a ratio of two integers, becomes:
- ✓
$\frac{103}{330}$
- B
$\frac{52}{165}$
- C
$\frac{103}{111}$
- D
$\frac{104}{333}$
AnswerCorrect option: A. $\frac{103}{330}$
View full question & answer→MCQ 351 Mark
When $8 . \overline{32}$ is expressed as a vulgar fraction, then it becomes:
- A
$\frac{208}{824}$
- ✓
$\frac{824}{99}$
- C
$\frac{800}{99}$
- D
$\frac{416}{45}$
AnswerCorrect option: B. $\frac{824}{99}$
View full question & answer→MCQ 361 Mark
Which of the following is a prime number?
View full question & answer→MCQ 371 Mark
Which of the following is an irrational number?
- A
- B
$2.7 \overline{2}$
- ✓
$\sqrt{11}$
- D
$\frac{2}{7}$
AnswerCorrect option: C. $\sqrt{11}$
View full question & answer→MCQ 381 Mark
Which of the following is a rational number?
View full question & answer→MCQ 391 Mark
Assertion (A) : Each of the numbers $\sqrt[3]{2}, \sqrt[3]{3}, \sqrt[3]{4}, \sqrt[3]{5}, \sqrt[3]{6}, \sqrt[3]{7}$ is irrational.
Reason (R) : The cube roots of all natural numbers is irrational.
View full question & answer→MCQ 401 Mark
Assertion (A) : The number obtained on rationalising the denominator of $\frac{1}{\sqrt{5}-2}$ is $2+\sqrt{5}.$
Reason (R) : If the product of two irrational numbers is rational, then each one is called the rationalising factor of the other.
View full question & answer→