Question 14 Marks
Prove that $: \tan \left(45^{\circ}- A \right) \tan \left(45^{\circ}+ A \right)=1$.
$\left[\right.$ Hint . $\left.\tan \left(45^{\circ}- A \right)=\tan \left[90^{\circ}-\left(45^{\circ}+ A \right)\right]=\cot \left(45^{\circ}+ A \right)\right]$.
$\left[\right.$ Hint . $\left.\tan \left(45^{\circ}- A \right)=\tan \left[90^{\circ}-\left(45^{\circ}+ A \right)\right]=\cot \left(45^{\circ}+ A \right)\right]$.
Answer
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