Download App

PHYSICS [2 Mark Question Answer]

Electricity and Magnetism - 1 · ICSE STD 9 (ICSE - English Medium). 10 questions.

Questions

[2 Mark Question Answer]

🎯

Test yourself on this topic

10 questions · timed · auto-graded

Question 12 Marks
Is it correct to say that a resistance wire is an insulator or a bad conductor? Explain your answer.
Answer
It is not correct to say that a resistance wire is an insulator or bad conductor. From resistance, it is implied that a gien material will conduct electricity, but will also offer obstruction to the passage of electric current.
View full question & answer→
Question 32 Marks
State two conditions necessary for a circuit, such that electric current flows through it.
Answer
For the flow of electric current through a circuit, following are the necessary conditions:
1. Electric circuit must be closed or complete.
2. Every part of the circuit is a conductor.
View full question & answer→
Question 42 Marks
What do you understand by the term electric cell?
Answer
Electric cell is an arrangement which maintains constant potential difference between conductors.
A cell basically consists of two conducting rods, which are called electrodes, immersed in a solution, which is called the electrolyte.
View full question & answer→
Question 52 Marks
A charge of 75 C is brought from infinity to a given point in an electric field, when amount of work done is 3.75 J . Calculate the electrical potential at that point.
Answer
$\begin{array}{l}\text { Charge }= Q =75 C \\ \text { Work done }= W =3.75 J \\ \text { Electric potential }= V =\text { ? } \\ V =\frac{ W }{ Q } \\ V =\frac{3.75}{75}=0.05 V\end{array}$
View full question & answer→
Question 62 Marks
What is the electrical potential at a point in an electric field when 24 J of work is done in moving a charge of 96 C from infinity?
Answer
$
\begin{array}{l}
\text { Electric potential }=V=\text { ? } \\
\text { Work, done }=W=24 J \\
\text { Charge }=Q=96 C \\
V=\frac{W}{Q} \\
V=\frac{24}{96}=\frac{1}{4} \\
V=0.25 V
\end{array}
$
View full question & answer→
Question 72 Marks
A dry cell can supply a charge of 800 C . If continuous current of 8.0 mA is drawn, calculate the time in which cell will discharge completely.
Answer
$\begin{array}{l}\text { Charge }= Q =800 C \\ \text { Electric current }= I =8.0 mA \\ I =8 \times 10^{-3} A \\ \text { Time }=t=? \\ I =\frac{ Q }{t} \\ t=\frac{ Q }{ I } \\ t=\frac{800}{8 \times 10^{-3}}=100 \times 10^3 \\ t=100000 s\end{array}$
View full question & answer→
Question 82 Marks
A battery can supply a charge of $25 \times 10^4$ C. If the current is drawn from battery at the rate of 2.5 A , calculate the time in which battery will discharge completely.
Answer
$\begin{array}{l}\text { Charge }= Q =25 \times 10^4 C \\ \text { Electric current }= I =2.5 A \\ \text { Time }=t=? \\ I =\frac{ Q }{t} \\ t=\frac{ Q }{ I } \\ t=\frac{25 \times 10^4}{2.5}=10^5 s \\ t=100000 s\end{array}$
View full question & answer→
Question 92 Marks
A charge of 8860 C flows through an electric circuit in 2 min and 40 s . Calculate the magnitude of current in circuit.
Answer
$\begin{aligned} \text {Charge} & =Q=8860 C \\
\text { Time }=t & =2 \min 40 s \\ t & =(2 \times 60+40) s \\ t & =160 s \end{aligned}$
Electric current $= I =$ ?
$\begin{array}{l} I=\frac{Q}{t}=\frac{8860}{160} \\ I=55.375 A \end{array}$
View full question & answer→
Question 102 Marks
A charge of 5000 C flows through an electric circuit in 2 hours and 30 minutes. Calculate the magnitude of current in circuit.
Answer
$\begin{array}{l}\text { Charge }=Q=5000 C \\
\text { Time }=t=2 \text { hour } 30 \text { minutes } \\
\quad \quad \quad\quad t=2 \times 60+30=150 min \\
\quad \quad \quad\quad t=150 \times 60 \text { second } \\
\quad \quad \quad\quad t=9000 \text { second } \\
\text { Electric current }=I=\text { ? } \\
I=\frac{Q}{t} \\
I=\frac{5000}{9000}=0.555 A\end{array}$
View full question & answer→
Generate Paper FreeAll Electricity and Magnetism - 1 topics
[2 Mark Question Answer] - PHYSICS STD 9 Questions - Vidyadip