Question 12 Marks
A jeweller claims to make ornaments of pure gold of relative density 19.3. A customer buys from him a bangle of weight 25.25 gf . The customer then weighs the bangle under water and finds its weight 23.075 g with the help of suitable calculations explain whether the bangle is of pure gold or not.
[R.D. of gold is 11.61 and bangle is not of pure gold] Ans. R.D of pure gold $=19.3$...given
[R.D. of gold is 11.61 and bangle is not of pure gold] Ans. R.D of pure gold $=19.3$...given
Answer
View full question & answer→R.D of pure gold $=19.3$
$
\text { Also R.D }=\frac{\text { weight of bangle in air }}{w t . \text { in air }-w t . \text { of bangle in water }}
$
R.D of gold $=\frac{25.25}{25.25-23.075}=\frac{25.25}{2.175}$
R.D of gold bangle $=11.75$ which is not as 19.3
Hence, gold is not PURE.
$
\text { Also R.D }=\frac{\text { weight of bangle in air }}{w t . \text { in air }-w t . \text { of bangle in water }}
$
R.D of gold $=\frac{25.25}{25.25-23.075}=\frac{25.25}{2.175}$
R.D of gold bangle $=11.75$ which is not as 19.3
Hence, gold is not PURE.