MCQ 11 Mark
Directions : In the following questions, a statement of assertion $(A)$ is followed by a statement of reason $(R).$ Mark the correct choice as:
Assertion : In the given figure, all the sides of a quadrilateral $\text{ABCD}$ touch a circle with centre $O.$ Then, $\angle\text{AOB}+\angle\text{COD}=180^\circ$
Reason : The opposite sides of a quadrilateral circumscribing a circle does not subtend supplementary angles at the centre of the circle.

Assertion : In the given figure, all the sides of a quadrilateral $\text{ABCD}$ touch a circle with centre $O.$ Then, $\angle\text{AOB}+\angle\text{COD}=180^\circ$
Reason : The opposite sides of a quadrilateral circumscribing a circle does not subtend supplementary angles at the centre of the circle.

- AAssertion and Reason both are correct statements and Reason is the correct explanation of Assertion.
- BAssertion and Reason both are correct statements but Reason is not the correct explanation of Assertion.
- ✓Assertion is correct statement but Reason is wrong statement.
- DAssertion is wrong statement but Reason is correct statement.
Answer
View full question & answer→Correct option: C.
Assertion is correct statement but Reason is wrong statement.
We have a circle with $R$ centre $O$.
A quadrilateral $\text{ABCD}$ is such that the sides $AB, BC, CD$ and $DA$ touch the circle at $P, Q, R$ and $S$ respectively.
Let us join $OP, OQ, QR$ and $OS.$
We know that two tangents drawn from an external point to a circle subtend equal angles at the centre.
$\therefore \angle1=\angle2,\angle3=\angle4$
$\angle5=\angle6$ and $\angle7=\angle8$
Also, the sum of all the angles around a point is $360^\circ$
$\therefore\angle1+ \angle2+ \angle3+ \angle4+ \angle5+ \angle6+ \angle7+\angle8 = 360^\circ$
$\Rightarrow 2[42+ 43+ 26+ 27] = 360^\circ $
$\Rightarrow(\angle2+\angle3) + (\angle6+\angle7) = 180^\circ$
Since, $\angle2 +\angle3 =\angle\text{AOB}, \angle6 + \angle7 = \angle\text{COD}$
$\angle\text{AOB} +\angle\text{COD} = 180^\circ $
$\therefore$ Assertion is correct and Reason is wrong.

A quadrilateral $\text{ABCD}$ is such that the sides $AB, BC, CD$ and $DA$ touch the circle at $P, Q, R$ and $S$ respectively.
Let us join $OP, OQ, QR$ and $OS.$
We know that two tangents drawn from an external point to a circle subtend equal angles at the centre.
$\therefore \angle1=\angle2,\angle3=\angle4$
$\angle5=\angle6$ and $\angle7=\angle8$
Also, the sum of all the angles around a point is $360^\circ$
$\therefore\angle1+ \angle2+ \angle3+ \angle4+ \angle5+ \angle6+ \angle7+\angle8 = 360^\circ$
$\Rightarrow 2[42+ 43+ 26+ 27] = 360^\circ $
$\Rightarrow(\angle2+\angle3) + (\angle6+\angle7) = 180^\circ$
Since, $\angle2 +\angle3 =\angle\text{AOB}, \angle6 + \angle7 = \angle\text{COD}$
$\angle\text{AOB} +\angle\text{COD} = 180^\circ $
$\therefore$ Assertion is correct and Reason is wrong.




