A circus tent is cylindrical to a height of 4m and conical above it. If its diameter is 105m and its slant height is 40m, then find the total area of the canvas required.
Answer
We have,
Height of the cylindrical part, H = 4m,
Radius of the base, $\text{r}=\frac{105}{2}\text{m}$ and
Slant height of the conical part, l = 40m
Now,
The total area of canvas required = CSA of conical part + CSA of cylindrical par
$=\pi\text{r}\text{l}+2\pi\text{r}\text{H}$
$=\pi\text{r}(\text{l}+2\text{H})$
$=\frac{22}{7}\times\frac{105}{2}\times40+2\times4$
$=11\times15\times48$
$=7920\text{m}^2$
So, the area of the canvas required to make the tent is $7920 m^2.$