M.C.Q - Science STD 10 Questions - Vidyadip

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18 questions · auto-graded multiple-choice test.

MCQ 11 Mark

What is the maximum resistance which can be made using five resistors each of $\frac{1}{5}\Omega$?

A
$\frac{1}{5}\Omega$
B
$10\Omega$
C
$5\Omega$
✓
$1\Omega$

Answer

Correct option: D.

$1\Omega$

When resistors are connected in series then we get the maximum resistance out of the combination. When the given resistors are connected in series, the resistance of combination can be calculated as follows:
$\text{R}=\frac{1}{5}+\frac{1}{5}+\frac{1}{5}+\frac{1}{5}+\frac{1}{5}=\frac{5}{5}=1\Omega$

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MCQ 21 Mark

A student carries out an experiment and plots the $V-I$ graph of three samples of nichrome wire with resistances $R_1, R_2$ and $R_3$ respectively $($Figure$)$. Which of the following is true?

A
$R_1 = R_2 = R_3$
B
$R_1 > R_2 > R_3$
✓
$R_3 > R_2 > R_1$
D
$R_2 > R_3 > R_1$

Answer

Correct option: C.

$R_3 > R_2 > R_1$

Slope of VI graph is proportional to $\frac{1}{\text { Resistance }}$.
It means when slope will be maximum, then resistance will be minimum.
From the figure, we can see that, slope of $R_1$ is maximum; hence its resistance will be minimum. As, slope of $R_3$ is minimum so, its resistance will be maximum.
Therefore, $R_3 > R_2 > R_1$.

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MCQ 31 Mark

In an electrical circuit three incandescent bulbs A, B and C of rating 40W, 60W and 100W respectively are connected in parallel to an electric source. Which of the following is likely to happen regarding their brightness?

A
Brightness of all the bulbs will be the same.
B
Brightness of bulb A will be the maximum.
✓
Brightness of bulb B will be more than that of A.
D
Brightness of bulb C will be less than that of B.

Answer

Correct option: C.

Brightness of bulb B will be more than that of A.

Since bulbs are connected in parallel so resistance of combination would be less than arithmetic sum of resistance of all the bulbs. So, there will be no negative effect on flow of current. As a result, bulbs would glow according to their wattage.

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MCQ 41 Mark

What is the minimum resistance which can be made using five resistors each of $\frac{1}{5}\Omega$?

A
$\frac{1}{5}\Omega$
✓
$\frac{1}{25}\Omega$
C
$\frac{1}{10}\Omega$
D
$25\Omega$

Answer

Correct option: B.

$\frac{1}{25}\Omega$

When resistors are connected in parallel then we get the minimum resistance out of the combination. When given resistors are connected in parallel, the resistance of combination can be calculated as follows:
$\frac{1}{\text{R}}=5+5+5+5+5=25\Omega$

Or $\text{R}=\frac{1}{25}\Omega$

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MCQ 51 Mark

A cell, a resistor, a key and ammeter are arranged as shown in the circuit diagrams of Figure. The current recorded in the ammeter will be:

A
Maximum in (i).
B
Maximum in (ii).
C
Maximum in (iii).
✓
The same in all the cases.

Answer

Correct option: D.

The same in all the cases.

Same current flows through every part of the circuit having resistance connected in series to a cell or battery.

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MCQ 61 Mark

Which of the following represents voltage?

✓
$\frac{\text{Work done}}{\text{Current}\times\text{Time}}$
B
$\text{Work done}\times\text{Charge}$
C
$\frac{\text{Work done}\times\text{Time}}{\text{Current}}$
D
$\text{Work done}\times\text{Charge}\times\text{Time}$

Answer

Correct option: A.

$\frac{\text{Work done}}{\text{Current}\times\text{Time}}$

Work done × Charge × Potential difference
⇒ Work done = (Current × Time) × Potential difference $[\because$ Charge = Current × Time$]$

⇒ Potential difference $=\frac{\text{Work done}}{\text{Current}\times\text{Time}}$

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MCQ 71 Mark

Unit of electric power may also be expressed as:

✓
Volt ampere.
B
Kilowatt hour.
C
Watt second.
D
Joule second.

Answer

Correct option: A.

Volt ampere.

Electric power = voltage × current
SI Unit of voltage = Volt

SI Unit of current = Ampere

So, unit of electric power is also given by, volt ampere.

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MCQ 81 Mark

In an electrical circuit two resistors of 2Ω and 4Ω respectively are connected in series to a 6V battery. The heat dissipated by the 4Ω resistor in 5s will be:

A
5J.
B
10J.
✓
20J.
D
30J.

Answer

Correct option: C.

20J.

Total resistance of combination $2\Omega+4\Omega=6\Omega$
Current through the circuit can be calculated as $\text{I}=\frac{\text{V}}{\text{R}}=\frac{6\text{V}}{6\Omega}=1\text{A}$
Heat dissipation by can be calculated as follows: $\text{H}=\text{I}^2\text{Rt}=(1\text{A})^2\times4\Omega\times5\text{s}=20\text{J}$

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MCQ 91 Mark

An electric kettle consumes 1kW of electric power when operated at 220V. A fuse wire of what rating must be used for it?

A
1A
B
2A
C
4A
✓
5A

Answer

Correct option: D.

5A

$\text{P}=\text{VI}$$\text{or I }=\frac{\text{P}}{\text{V}}=\frac{1\text{kW}}{220\text{V}}$
$=\frac{1000\text{W}}{220\text{A}}=4.55\Omega=5\text{A}$

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MCQ 101 Mark

In the following circuits (Figure), heat produced in the resistor or combination of resistors connected to a 12V battery will be:

A
Same in all the cases.
B
Minimum in case (i).
✓
Maximum in case (ii).
D
Maximum in case (iii).

Answer

Correct option: C.

Maximum in case (ii).

In this case, two resistors are in series. Hence, their sum will be equal to their arithmetic sum. In figure (iii) the total resistance will be less than individual resistances because they are connected in parallel. A higher resistance produces more heat so option (c) is correct.

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MCQ 111 Mark

A cylindrical conductor of length l and uniform area of crosssection A has resistance R. Another conductor of length 2l and resistance R of the same material has area of cross section:

A
$\frac{\text{A}}{2}$
B
$\frac{3\text{A}}{2}$
✓
$2\text{A}$
D
$3\text{A}$

Answer

Correct option: C.

$2\text{A}$

$\text{R}=\rho\frac{\text{l}}{\text{A}}\ ....(\text{i})$Also, $\text{R}=\frac{\rho(2\text{l})}{\text{A}'}\ ....(\text{ii})$
From eq. (i) and (ii)
$\frac{1}{\text{A}}=\frac{2}{\text{A}'}\text{ or A}'=2\text{A}$

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MCQ 121 Mark

A current of $1A$ is drawn by a filament of an electric bulb. Number of electrons passing through a cross section of the filament in $16$ seconds would be roughly:

✓
$10^{20}$
B
$10^{16}$
C
$10^{18}$
D
$10^{23}$

Answer

Correct option: A.

$10^{20}$

$\text{I}=\frac{\text{Q}}{\text{t}}=\frac{\text{ne}}{\text{t}}$
$\text{n}=\frac{\text{It}}{\text{e}}=\frac{1\times16}{1.6\times10^{-19}}=10^{20}$

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MCQ 131 Mark

Two resistors of resistance 2Ω and 4Ω when connected to a battery will have:

A
Same current flowing through them when connected in parallel.
✓
Same current flowing through them when connected in series.
C
Same potential difference across them when connected in series.
D
Different potential difference across them when connected in parallel.

Answer

Correct option: B.

Same current flowing through them when connected in series.

In series combination of resistor, the current through both the resistor are same but potential difference across each will be different.
In parallel combination current across each resistor will be different but the potential difference will be same.

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MCQ 141 Mark

If the current I through a resistor is increased by $100\% ($assume that temperature remains unchanged$)$, the increase in power dissipated will be:

A
$100\%$
B
$200\%$
✓
$300\%$
D
$400\%$

Answer

Correct option: C.

$300\%$

The heat generated by a resistor is directly proportional to square of current. Hence, when current becomes double, dissipation of heat will multiply by $2^2 = 4$. This means there will be an increase of $300\%.$

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MCQ 151 Mark

Electrical resistivity of a given metallic wire depends upon:

A
Its length.
B
Its thickness.
C
Its shape.
✓
Nature of the material.

Answer

Correct option: D.

Nature of the material.

The resistivity of a material is constant for a particular temperature at a constant temperature.
Resistivity of material does not depend on length, thickness and shape of the material. It only depends on the temperature.

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MCQ 161 Mark

Identify the circuit $($Figure$)$ in which the electrical components have been properly connected.

A
$(i)$
✓
$(ii)$
C
$(iii)$
D
$(iv)$

Answer

Correct option: B.

$(ii)$

Essential conditions are necessary when electrical components are connected :

Voltmeter should be connected in parallel.
Ammeter is always connected in series.
Positive terminals of voltmeter and ammeter should be connected to positive terminal of the cell and their negative terminals should be joined to the negative terminal of the cell.

Thus, the above conditions are satisfied in case $(ii).$

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MCQ 171 Mark

The proper representation of series combination of cells (Figure) obtaining maximum potential is:

A
(i)
B
(ii)
C
(iii)
✓
(iv)

Answer

Correct option: D.

(iv)

Cells are connected in series if -ve terminal of one cell is connected to the +ve terminal of other cell.

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MCQ 181 Mark

The resistivity does not change if:

A
The material is changed.
B
The temperature is changed.
✓
The shape of the resistor is changed.
D
Both material and temperature are changed.

Answer

Correct option: C.

The shape of the resistor is changed.

Resistivity of material does not depend on its dimensions and shape. However, resistivity depends upon the temperature and the nature of material.

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M.C.Q - Science STD 10 Questions - Vidyadip