Maths M.C.Q. [1 Marks Each]

$2\ km 35m = 2.035\ km$
($\because$ $1000m = 1\ km)$

given that, $617.0000 + 6.0170 + 0.6170 + 6.0017 = 629.6357$

$5$ is in the thousandth place.
$0.04532=\frac{4}{100}+\frac{5}{1000}+\frac{3}{10000}+\frac{2}{100000}$

$\therefore9.02=5.7=3.32$

Expanded form of $78.059$ is $7+8+0+\frac{5}{100}+\frac{9}{1000}$

$626.235$
There are two 6s in this number, one at Hundreds place and other at Ones place.
$\Rightarrow $ Place values of $6 = 6 \times 100$ and $6 \times 1$
Difference $= 600 - 6 = 594$

To find the percent of a given number, we will multiply it with $100$
Let the number in decimal be $x$
The number in percent is $12\frac{1}{4} = \frac{49}{4}$
When converted to percent, the number becomes $\text{x}\times100= \frac{49}{4}$'
$\Rightarrow \text{x}=\dfrac{49}{400} =0.1225$

Expanded form of $920831$
$900000 + 20000 + 800 + 30 + 1$

$32.000 - 27.091 = 4.909$

$4+\frac{3}{100}=\frac{400+3}{100}=4.03$

$\frac{7}{100}$ is equal to $0.07$. Since the denominator is $100$, we have to mark the decimal such that $7$ is in the hundredth place.

$600.065 = 600 + 0.65 + 0.001$

To add 3 decimal numbers of different decimal values we pick the number with the highest decimal
value and expand all the other numbers to the same value by adding $0$ after the decimal point.
$0.300 + 0.030 + 0.003 = 0.333$

The fraction $\frac{9}{10}$ in decimal form is $0.9$

Difference in pocket money of Madhu and Srinu $= 4.25 - 3.75 = 0.50$
Difference in one week $= 0.50 \times 7 = 3.50$

$4\frac{7}{8}=4+\frac{7\times125}{8\times125}$
$=4+\frac{875}{1000}$
$=4+0.875$
$=4.875$

To write it as a decimal we divide the numerator from the denominator $\frac{9}{1000}=0.009$
So, $0.009$ is the decimal representation for $\frac{9}{1000}$

$2.5 + 3.05 - 4.005$
$= 5.55 - 4.005$
$= 1.545$

$2\ m \ 5\ cm = 2.05\ m$

To round to the nearest tenth, write down the number with a decimal point, and find the tenths place directly to the right of the decimal.
Then, to the right of the tenths place, look at the number in the hundredths place.
In $6050.287$ the number in the hundredths is $2.2.$
So, $6050.287$ rounded to the nearest tenths will be $6050.3$

The sum of two numbers $= 31.021$
One of the numbers $= 11.560$
Other number $= 31.021 - 11.560 = 19.461$

The value of $2.\overline{6}-1.\overline{9}$ is
$=\Big(2+\frac{6}{9}\Big)-\Big(1+\frac{9}{9}\Big)$
$=\frac{6}{9}=0.\overline{6}$

We know that $100\ cm = 1m.$
Therefore, $1\text{cm}=\frac{1}{100}\text{m}=0.01\text{m.}$

Converting into like decimals:
$\ \ \ 5.01\\ \underline{-3.60}\\ \underline{\ \ \ 1.41}$

$1\text{cm}=\frac{1}{100}\text{m}$
$=0.01$

Since the denominator is $1000$, we have to mark the decimal such that $4$ is in the thousandth place.

$\frac{3}{10}=0.3$ (since the denominator is $10$, we need to mark the decimal such that $3$ is in the tenth place).
$\frac{5}{100}=0.05$ (since the denominator is $100$, we need to mark the decimal such that $5$ is in the hundredth place).
Therefore, $2+\frac{3}{10}+\frac{5}{100}=2+0.3+0.05$
$=2.35$

$\frac{16}{1000}=0.016$

$\begin{aligned}
&\begin{aligned}
& 1 \\
& 12.56 \\
& +0.50 \\
& \hline 13.06 \\
& \\
& 13.060 \\
& +0.003 \\
& \hline 13.063
\end{aligned}\\
&\text { Option A is correct. }
\end{aligned}$

$95.75 \times 0.2554 = 24.45455$
Sum of decimal places $= 7$ Since the last digit to the extreme right will be zero
(since $5 \times 4 = 20)$, so there will be $5$ significant digits to the right of the decimal point.

$\frac{4}{20}=\frac{4}{20}\times\frac{5}{5}=\frac{20}{100}=0.20$

$2\frac{1}{25}=2+\frac{1}{25}$
$=2+\frac{1\times4}{25\times4}$
$=2+\frac{4}{100}$
$=2+0.04$
$=2.04$

For obtaining the sum of decimal numbers with different decimal values we expand the decimal
values of all the numbers with respect to the number with the highest decimal value.
Because the number with the largest decimal places is $72.985$ with $3$ decimal places, we expand all numbers up to $3$ decimal places.$1.800 + 16.300 + 72.985 = 91.085$

Converting decimal into fraction $0.6=\frac{6}{10}$